Question

PLEASE HELP!!!! ASAPP

Answer 1

Answer:

.056

Explanation:

750*1.35/

62.396*290=.05595778

n=.056

Answer 2

Answer : The number of moles of air present is, 0.055 mole

Solution :

Using ideal gas equation :

$PV=nRT$

where,

P = pressure of the gas = 750 torr = 0.98 atm      (1 atm = 760 torr)

V = volume of the gas = 1.35 L

T = temperature of the gas = $17^oC=17+273=290K$

R = gas constant = 0.0821 Latm/moleK

n = number of moles of air = ?

Now put all the given values in this formula, we get the number of moles of air present.

$(0.98atm)\times (1.35L)=n\times (0.0821Latm/moleK)\times (290K)$

$n=0.055mole$

Therefore, the number of moles of air present is, 0.055 mole