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kolezko [41]
3 years ago
7

PLEASE HELP!!!! ASAPP

Chemistry
2 answers:
miv72 [106K]3 years ago
5 0

Answer:

.056

Explanation:

750*1.35/

62.396*290=.05595778

n=.056

kirza4 [7]3 years ago
3 0

Answer : The number of moles of air present is, 0.055 mole

Solution :

Using ideal gas equation :

PV=nRT

where,

P = pressure of the gas = 750 torr = 0.98 atm      (1 atm = 760 torr)

V = volume of the gas = 1.35 L

T = temperature of the gas = 17^oC=17+273=290K

R = gas constant = 0.0821 Latm/moleK

n = number of moles of air = ?

Now put all the given values in this formula, we get the number of moles of air present.

(0.98atm)\times (1.35L)=n\times (0.0821Latm/moleK)\times (290K)

n=0.055mole

Therefore, the number of moles of air present is, 0.055 mole

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