Answer:
It isnt changing
Explanation:
It stays basically the same becuase it is considered a constant
Answer: 12 electrons
<u>If the 3d and 4s bands are superimposed on a metal atom, the maximum number of electrons for this band will be 12 electrons.</u> Remember that in layer 10 you can enter up to 10 electrons in the orbitals that you have, while the s can enter 2, therefore the amount of electrons that will enter the set formed by both bands when superimposed will be 12 electrons
Answer : The concentration of NO is, 
Solution : Given,
Concentration of 
and 
= 152 M
Equilibrium constant, 
= 
The given equilibrium reaction is,
The expression of will be,
![K_c=\frac{[NO]^2}{[N_2][O_2]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BNO%5D%5E2%7D%7B%5BN_2%5D%5BO_2%5D%7D)
Now put all the given values in this expression, we get:
![2.0\times 10^{-9}=\frac{[NO]^2}{152\times 152}](https://tex.z-dn.net/?f=2.0%5Ctimes%2010%5E%7B-9%7D%3D%5Cfrac%7B%5BNO%5D%5E2%7D%7B152%5Ctimes%20152%7D)
![[NO]=6.8\times 10^{-3}M](https://tex.z-dn.net/?f=%5BNO%5D%3D6.8%5Ctimes%2010%5E%7B-3%7DM)
Therefore, the concentration of NO is,
Answer:
See explanation
Explanation:
Dilution law= C1V1=C2V2.
Where C is the concentration in mol per dm cube and V= volume in dm cube.
From the questions the parameters given are; V= 42.5ZmL, concentration or molarity of HCl= 0.193M and the molarity of KOH = 0.125M.
(a). At 0mL where the base KOH has not been added yet.
Moles of HCl = molarity × volume.
Moles of HCl = 0.193 × 42.5/1000
Moles of HCl= 0.00820205
pH=- log 0.0082025
pH= 2.086
Approximately, pH=2.1.
(b). At 3mL of 0.125M KOH
3/1000 × 0.125 mol/L
= 0.003L× 0.125 M
= 0.000375 moles KOH
Determining the number of moles of HCl, we have;
42.5/1000 × 0.193 mol/L
= 0.0082025
Final volume= 3mL+42.5mL= 45.5 ml
Final[HCl] = 0.0082025 - 0.000375 = 0.0078275.
Therefore, 0.0078275/ 0.0455
= 0.1720
pH= -log 0.1720
pH= 0.76.
(c). 5mL of 0.125M KOH
5/1000 × 0.125
= 0.005×0.125
= 0.000625 mol KOH
42.5/1000 × 0.193 mol/L
= 0.0082025 mol
Final volume= 5mL + 42.5= 47.5 mL.
0.0082025-0.000625= 0.0076
Final [HCl] = 0.0076/0.0475
= 0.16
pH= -log 0.16
pH= 0.79.
