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DiKsa [7]
3 years ago
5

How many electrons will one atom of element with 6 protons and 9 neutrons .

Chemistry
1 answer:
ira [324]3 years ago
4 0

Answer:

The atomic mass of this element would be 12 amu

Explanation:

The subatomic particles provide several bits of information about a given element.

The number of protons is equal to the atomic number of the element. For this element having 6 protons makes the atomic number 6 and makes the element Carbon.

The number of protons plus the number of neutrons equals the atomic mass of the element based upon atomic mass units (amus)

For this element 6 protons and 6 neutrons combine to make an atomic mass of 12 amus.

Lastly, the values of protons and electrons tell whether the atom is an ion or neutral. When protons equal electrons the atom is neutral. When protons are greater than neutrons the atom is a positive charge or cation. When the protons are less than the electrons the atom is a negative charge or anion. For this example the Carbon atom has 6 protons and 6 electrons making it neutral.

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How many oxygen atoms are in a representative particle of each substance?
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Balance<br> Sn(s) + HNO3(aq) →SnO2(s) + NO2(g) + H2O(1)
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Convert 345 g to kilograms (kg).<br> 1 kg = 1000 g<br> (please show work) ASAP
astraxan [27]

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6 0
3 years ago
During a combustion reaction, 9.00 grams of oxygen reacted with 3.00 grams of CH4.
Monica [59]

Answer:

0.74 grams of methane

Explanation:

The balanced equation of the combustion reaction of methane with oxygen is:

  • CH₄ + 2 O₂ → CO₂ + 2 H₂O

it is clear that 1 mol of CH₄ reacts with 2 mol of O₂.

firstly, we need to calculate the number of moles of both

for CH₄:

number of moles = mass / molar mass = (3.00 g) /  (16.00 g/mol) = 0.1875 mol.

for O₂:

number of moles = mass / molar mass = (9.00 g) /  (32.00 g/mol) = 0.2812 mol.

  • it is clear that O₂ is the limiting reactant and methane will leftover.

using cross multiplication

1 mol of  CH₄ needs → 2 mol of O₂

???  mol of  CH₄  needs → 0.2812 mol of O₂

∴ the number of mol of CH₄ needed = (0.2812 * 1) / 2 = 0.1406 mol

so 0.14 mol will react and the remaining CH₄

mol of CH₄ left over = 0.1875 -0.1406 = 0.0469 mol

now we convert moles into grams

mass of CH₄ left over = no. of mol of CH₄ left over *  molar mass

                                    = 0.0469 mol * 16 g/mol = 0.7504 g

So, the right choice is 0.74 grams of methane

3 0
3 years ago
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