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Triss [41]
3 years ago
11

A new engine is being designed that will carry 5.430 x 102 kilograms of methane, CH4, on board. How many liters of gaseous oxyge

n needs to be carried on board to ensure complete combustion? The oxygen will be stored at 3.500 atm of pressure and -170.84 °C. Use four significant figures in your answer. Hint: write out the balanced chemical reaction. Assume the gas behaves ideally.
(If you don't know don't answer. It takes up the points I worked really hard for for people who work equally as hard to help me understand these concepts)
Chemistry
1 answer:
algol [13]3 years ago
7 0

Answer:

yeet

Explanation:

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15. What are the five things that influence weather?
const2013 [10]
Wind
air pressure
temperature
humidity
clouds
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3 years ago
Hydrochloric acid is used to produce fertilizers and dyes, to pickle and clean metal products, and as a reagent in the photograp
neonofarm [45]

Answer:

Hydrochloric acid reacts with the materials to produce bubbling, or fizzing, a gas, and heat.

Explanation:

3 0
3 years ago
Match each chemical with the correct use.
Fittoniya [83]

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7 0
4 years ago
A chemistry student needs of acetic acid for an experiment. He has available of a w/w solution of acetic acid in acetone. Calcul
Volgvan

Answer:

49.4 g Solution

Explanation:

There is some info missing. I think this is the original question.

<em>A chemistry student needs 20.0g of acetic acid for an experiment. He has 400.g  available of a 40.5 %  w/w solution of acetic acid in acetone.  </em>

<em> Calculate the mass of solution the student should use. If there's not enough solution, press the "No solution" button. Round your answer to 3 significant digits.</em>

<em />

We have 400 g of solution and there are 40.5 g of solute (acetic acid) per 100 grams of solution. We can use this info to find the mass of acetic acid in the solution.

400gSolution \times \frac{40.5gSolute}{100gSolution} = 162 g Solute

Since we only need 20.0 g of acetic acid, there is enough of it in the solution. The mass of solution that contains 20.0 g of solute is:

20.0gSolute \times \frac{100gSolution}{40.5gSolute} = 49.4g Solution

4 0
3 years ago
How many moles of NaCl are there in 6.93g?
kkurt [141]
8.43
58.44g/mol*1/6.93g= 8.43moles of NaCL
5 0
3 years ago
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