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77julia77 [94]
3 years ago
11

At an aquarium, a tour of the shark tanks begins every 45 minutes. The dolphin show begins every 30 minutes. If the shark tour a

nd the dolphin show both start at 9am, at what time will they start at the same time again? Explain your answer
Mathematics
2 answers:
bixtya [17]3 years ago
7 0
10:30 cause the the fourth dolphin show is 10:30 and third shark tank tour starts at 10:30

Hope this helps
Vera_Pavlovna [14]3 years ago
7 0
The answer would be 10:30. This would be because the fourth dolphin show would be at 10:30 and then the shark would start at 10:30
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If the E(X) = 1 then that means it has a 100% which is incorrect.
Each block has an equal probability to contain the error so 1/3 because you choose 2/6.
5 0
3 years ago
The table below represents a linear relationship. What is the slope of the line?
stealth61 [152]

Answer: side ways

Step-by-step explanation:

5 0
2 years ago
19.<br>How long is the pencil shown below?<br>3.5<br>1 2<br>3<br>4<br>5 cm​
arlik [135]
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6 0
3 years ago
EXPLAIN why we placed the value of x= 4/3( the minimum value) into the equ of gradient(dy/dx) [in the answer, marking scheme att
aliina [53]
y=x(x-2)^2
\implies y'=(x-2)^2+2x(x-2)=3x^2-8x+4=(3x-2)(x-2)=0
\implies x=\dfrac23,x=2

are the critical points, and judging by the picture alone, you must have b=\dfrac23 and a=2. (You might want to verify with the derivative test in case that's expected.)

Then the shaded region has area

\displaystyle\int_0^2x(x-2)^2\,\mathrm dx=\dfrac43

I'll leave the details to you.

Now, for part (iv), you're asked to find the minimum of \dfrac{\mathrm dy}{\mathrm dx}=y', which entails first finding the second derivative:

y'=3x^2-8x+4
\implies y''=6x-8

setting equal to 0 and finding the critical point:

6x-8=0\implies x=\dfrac86=\dfrac43

This is to say the minimum value of \dfrac{\mathrm dy}{\mathrm dx} *occurs when x=\dfrac43*, but this is not necessarily the same as saying that \dfrac43 is the actual minimum value.

The minimum value of \dfrac{\mathrm dy}{\mathrm dx} is obtained by evaluating the derivative at this critical point:

m=\dfrac{\mathrm dy}{\mathrm dx}\bigg|_{x=4/3}=3\left(\dfrac43\right)^2-8\left(\dfrac43\right)+4=-\dfrac43
4 0
3 years ago
Cláudio pode ir de sua casa a escola andando três km para o Norte, 2 para o oeste, um para o sul, quatro para o leste e, finalme
VARVARA [1.3K]

Answer:

b) 2 Km para o leste

Step-by-step explanation:

1. 2 km N

2. 2 km W

3. 1 km S

4. 4 km E

5. 2 km S

Sul e Norte:

(1.) 2 km N + (3.) 1 km S + (5.) 2 km S = 2 km - 1 km - 2 km = 0

Este e Oeste:

(2.) 2 km W + (4.) 4 km E = -2 km + 4 km = 2 km E

Veja imagem abaixo.

7 0
2 years ago
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