I think you multiply them both from the area
Answer:
The probability is 0.003
Step-by-step explanation:
We know that the average
is:
![\mu=500](https://tex.z-dn.net/?f=%5Cmu%3D500)
The standard deviation
is:
![\sigma=100](https://tex.z-dn.net/?f=%5Csigma%3D100)
The Z-score is:
![Z=\frac{x-\mu}{\sigma}](https://tex.z-dn.net/?f=Z%3D%5Cfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D)
We seek to find
![P(x800)](https://tex.z-dn.net/?f=P%28x%3C200%5C%20or%5C%20x%3E800%29)
For P(x>800) The Z-score is:
![Z=\frac{x-\mu}{\sigma}](https://tex.z-dn.net/?f=Z%3D%5Cfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D)
![Z=\frac{800-500}{100}](https://tex.z-dn.net/?f=Z%3D%5Cfrac%7B800-500%7D%7B100%7D)
![Z=3](https://tex.z-dn.net/?f=Z%3D3)
The score of Z = 3 means that 800 is 3 standard deviations from the mean. Then by the rule of the 8 parts of the normal curve, the area that satisfies the conficion of 3 deviations from the mean has percentage of 0.15%
So
![P(x>800)=0.15\%](https://tex.z-dn.net/?f=P%28x%3E800%29%3D0.15%5C%25)
For P(x<200) The Z-score is:
![Z=\frac{x-\mu}{\sigma}](https://tex.z-dn.net/?f=Z%3D%5Cfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D)
![Z=\frac{200-500}{100}](https://tex.z-dn.net/?f=Z%3D%5Cfrac%7B200-500%7D%7B100%7D)
![Z=-3](https://tex.z-dn.net/?f=Z%3D-3)
The score of Z = -3 means that 200 is 3 standard deviations from the mean. Then by the rule of the 8 parts of the normal curve, the area that satisfies the conficion of 3 deviations from the mean has percentage of 0.15%
So
![P(x](https://tex.z-dn.net/?f=P%28x%3C200%29%3D0.0015)
Therefore
![P(x800)=P(x800)](https://tex.z-dn.net/?f=P%28x%3C200%5C%20or%5C%20x%3E800%29%3DP%28x%3C200%29%20%2BP%28x%3E800%29)
![P(x800)=0.0015 + 0.0015](https://tex.z-dn.net/?f=P%28x%3C200%5C%20or%5C%20x%3E800%29%3D0.0015%20%2B%200.0015)
![P(x800)=0.003](https://tex.z-dn.net/?f=P%28x%3C200%5C%20or%5C%20x%3E800%29%3D0.003)
Answer:
4x² / 4x² = 1
Step-by-step explanation:
Anything divided by itself is always 1
Step-by-step explanation:
![4(y - 3) = 13 \\ \\ \therefore \: 4y - 4 \times 3 = 13 \\ \\ \therefore \: 4y - 12 = 13\\ \\ \therefore \: 4y = 13 + 12 \\ \\ \therefore \: 4y = 25 \\ \\ \therefore \:y = \frac{25}{4} \\ \\ \therefore \:y = 6\frac{1}{4}](https://tex.z-dn.net/?f=4%28y%20-%203%29%20%3D%2013%20%5C%5C%20%20%5C%5C%20%20%5Ctherefore%20%5C%3A%204y%20-%204%20%5Ctimes%203%20%3D%2013%20%5C%5C%20%20%5C%5C%20%20%5Ctherefore%20%5C%3A%204y%20-%2012%20%3D%2013%5C%5C%20%20%5C%5C%20%20%5Ctherefore%20%5C%3A%204y%20%20%3D%2013%20%2B%2012%20%5C%5C%20%20%5C%5C%20%20%5Ctherefore%20%5C%3A%204y%20%20%3D%2025%20%5C%5C%20%20%5C%5C%20%5Ctherefore%20%5C%3Ay%20%3D%20%20%5Cfrac%7B25%7D%7B4%7D%20%20%5C%5C%20%20%5C%5C%20%5Ctherefore%20%5C%3Ay%20%3D%20%206%5Cfrac%7B1%7D%7B4%7D%20)