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Brums [2.3K]
3 years ago
7

Solve the following for y: p(t + 4) = 2y

Mathematics
1 answer:
dimulka [17.4K]3 years ago
6 0

Answer:

the answer is y =p(t + 4)/2

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Salsk061 [2.6K]
Angle 4 is the same as angle 6, 75 degrees, there are alternate interior angles.

8 0
3 years ago
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What is the formula for the following arithmetic sequence?
vlabodo [156]

a_{n} = 12 + (- 6)(n - 1 )

This is an arithmetic sequence with n th term

a_{n} = a_{1} + (n - 1)d

here d = - 6 - 0 = 0 - 6 = 6 - 12 = -6 and a_{1} = 12, hence

a_{n} = 12 + (- 6)(n - 1)

use this formula to find the 30 th term

a_{30} = 12 + (- 6 × 29) = 12 - 174 = - 162



4 0
4 years ago
Solve for x.<br><br> I need help please
Pachacha [2.7K]
It’s 1/4...............
3 0
3 years ago
541 (484) 783, 437 (?) 642​
alexandr402 [8]

Answer:

541 (484) 783, 437 (410) 642​

Step-by-step explanation:

Required

Fill in the bracket

First, we generate a formula for the first sequence: 541 (484) 783

484 = 2 * [783 - 541]

484 = 2 * [242]

484 = 2 * 242

484 = 484

Using the same formula for the second sequence: 437 (?) 642​

x = 2 * [642 - 437]

Where x represents the empty bracket

x = 2 * [205]

x = 2 * 205

x = 410

3 0
3 years ago
PLEASE HELPPP
Y_Kistochka [10]

The function f(x)=(x-2)^3+8 is one-to-one and the inverse of f(x) is f^{-1} (x)=(x-8)^\frac{1}{3}+2.

A function is one-to-one if for f(a)=f(b), we show that a=b.

f(a)=(a-2)^3+8

f(b)=(b-2)^3+8

Take f(a)=f(b)

(a-2)^3+8=(b-2)^3+8

(a-2)^3=(b-2)^3

Let A=a-2 and B=b-2

If A^3=B^3, then A=B.

So, a-2=b-2

a=b.

So, the function is one-to-one.

For the inverse of f(x), replace x with y and solve for y.

x=(y-2)^3+8

(y-2)^3=x-8

y-2=(x-8)^\frac{1}{3}

y=(x-8)^\frac{1}{3}+2

So, the inverse of f(x) is y=(x-8)^\frac{1}{3}+2.

Learn more about and inverse of a function here:

brainly.com/question/2541698?referrer=searchResults

5 0
2 years ago
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