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3 years ago

What can you say about the given and the grouping in [100•(-1)]•(-2) and 100• [(-1)• (-2)

1 answer:

5 0

I could say that they will give you different answers since they are the same numbers and are in the same order but are paired differently

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Why is it helpful to write numbers in different ways

Goshia [24]

You should write numbers in as many ways as you possibly can to make new connections in your brain. Knowing how to write numbers in many different ways can help you solve complex problems more easily. Doing this can also reinforce the mathematical principles and logic you have memorised.

Writing one in many different ways:

1=1/1=2/2=3/3=4/4=(-1)/(-1)=(-2)/(-2)

=1.0=1.00=1.000=(1/2)+(1/2)=(1/3)+(1/3)+(1/3)

=(1/4)+(1/4)+(1/4)+(1/4)

Writing a half in many different ways:

1/2=(1/4)+(1/4)=(1/6)+(1/6)+(1/6)

=(1/8)+(1/8)+(1/8)+(1/8)=4*(1/8)

=2/4=3/6=4/8=5/10=0.5=0.50

etc...etc...

6 0

3 years ago

Kelly used 3 2/9 packs of notebook paper in the first 1/6 of the year. At what rate is Kelly using notebook paper.

Makovka662 [10]

Answer:

jsjdhhdbdbnsndnnrnrnrnnsjdbbrbrnnrbr

4 0

3 years ago

Ill give brainiest, dont guess please

andrew-mc [135]

I don't know the first one but the second one is The second national bank was chartered in 1816.

4 0

3 years ago

Read 2 more answers

Can someone please help me with math.

sergeinik [125]

15. -2
16. A. The pool was originally empty

7 0

3 years ago

A national study report indicated that 20.9% of Americans were identified as having medical bill financial issues. What if a ne

Alenkasestr [34]

Answer:

The p-value for this test is 0.22065.

Step-by-step explanation:

We are given that a national study report indicated that 20.9% of Americans were identified as having medical bill financial issues.

A news organization randomly sampled 400 Americans from 10 cities and found that 90 reported having such difficulty.

Let p = proportion of Americans who were identified as having medical bill financial issues in 10 cities.

SO, Null Hypothesis, $H_0$ : p $\leq$ 20.9% {means that % of Americans who were identified as having medical bill financial issues in these 10 cities is less than or equal to 20.9%}

Alternate Hypothesis, $H_A$ : p > 20.9% {means that % of Americans who were identified as having medical bill financial issues in these 10 cities is more than 20.9% and is more severe}

The test statistics that will be used here is One-sample z proportion statistics;

T.S. = $\frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of 400 Americans from 10 cities who were found having such difficulty = $\frac{90}{400}$ = 0.225 or 22.5%

n = sample of Americans = 400

So, test statistics = $\frac{0.225-0.209}{{\sqrt{\frac{0.225(1-0.225)}{400} } } } }$

= 0.77

Now, P-value of the test statistics is given by the following formula;

P-value = P(Z > 0.77) = 1 - P(Z $\leq$ 0.77)

= 1 - 0.77935 = 0.22065

5 0

3 years ago

What can you say about the given and the grouping in [100•(-1)]•(-2) and 100• [(-1)• (-2)​

What can you say about the given and the grouping in [100•(-1)]•(-2) and 100• [(-1)• (-2)