Question

4x^2-16x-5 can be written in vertex form f(x)=a(x-h)^2+k. What are the values of a,h, and k.

Answer 1

Answer:

h=2

a=4

k= -21

Step-by-step explanation:

your h and k are vertex . h= x coordinate of vertex and k= y

so formula for vertex coordinates is x= -b/2a and y= (4ac-b²)/4a

your a b c are 4 -16 and -5 respectively according to the main equation

your a is concavity which is the same number as the 'a' of the equation