4x^2-16x-5 can be written in vertex form f(x)=a(x-h)^2+k.
What are the values of a,h, and k.
1 answer:
Answer:
h=2
a=4
k= -21
Step-by-step explanation:
your h and k are vertex . h= x coordinate of vertex and k= y
so formula for vertex coordinates is x= -b/2a and y= (4ac-b²)/4a
your a b c are 4 -16 and -5 respectively according to the main equation
your a is concavity which is the same number as the 'a' of the equation
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