Answer:
<h3>here its simple 0506-5-569756'567o5[76]5567=-5670;675;'6776[5]675</h3>
Step-by-step explanation:
oh and 340450=043=4-re0t4=24--44035054-23=0-65-=302=44934205=-3043504-3=-4-334=-043-40==34=40-[;'30=43-4=053=-=
Principal: $49,000
Depreciation Rate: 50%
Depreciation Time: 5 years
Exponential Function: y = 49,000 (0.50)^x
Plug it in: y = 49,000 (0.50)^4
0.5^4= 0.0625
0.0625 x 49,000 = 3062.5
Value of Car after 20 years: 3062.5
Now, we need to find out how much the car decreases in ONE year.
Half of 3062.5 = 1531.25
1531.25/5 = 306.25
3062.5 - 306.25 = 2756.25
Value of car after 21 years: $2756 ---> 2800 (nearest hundred dollars my bad)
Hope this helps! Have a great day!
Answer:
Kenny is 18 years old Andrew is 10 years old Tim is 30 years old and Cameron is 5 years old
Step-by-step explanation:
Let a be Kenny's age , b be Andrew's age , c be Tim's age , d be Cameron's age
( b < a , b<c , d<b)
Kenny is 8 years older than Andrewn = > a = b + 8 (1)
Tim is 3 times as old as Andrew => c = 3 . b (2)
Cameron is 5 years younger than Andrew => d = b-5 (3)
The combined age of the four is 63 => a+b+c+d = 63 (4)
(1),(2),(3),(4) => b+8 + b + 3b + b-5 = 63 <=> 6b + 3 = 63 <=> b = 10
=> a= 10+8 =18, c = 3 . 10 = 30, d= 5
Answer:
Domain = 1 to 7
Range = 4 to 28
Step-by-step explanation:
Given that:
Number of wheels used is a function of number of cars manufactured.
Number of wheels present = 28
1 car uses 4 wheels
2 cars use 8 wheels.
3 car uses 12 wheels
and so on.
Let the function be of the form:
Domain of the function is the value of 
that can be given as valid input to the function.
Range of the function is the value of 
that can be output of the function.
Let be the number of cars manufactured.
Then value of is nothing but times 4.
We are given that maximum value of can be 28.
Therefore, maximum value of input can be 7.
Minimum number of wheels can be 4 to make a minimum of 1 car.
Therefore domain is 4 to 28 and range is 1 to 7.
