The probability that a randomly selected 2 2-year-old male garter snake garter snake will live to be 3 3 years old is 0.98861 0
1 answer:
Answer:
a.
b.
c.
No, it is not unusual if at least 1 lives up to 3.
Step-by-step explanation:
Given
Represent the probability that a 2 year old snake will live to 3 with P(Live);
Solving (a): Probability that two selected will live to 3 years.
Both snakes have a chance of 0.98861 to live up to 3 years.
So, the required probability is:
<em>--- Approximated</em>
Solving (b): Probability that seven selected will live to 3 years.
All 7 snakes have a chance of 0.98861 to live up to 3 years.
So, the required probability is:
Where
<em>--- Approximated</em>
Solving (c): Probability that at least one of seven selected will not live to 3 years.
In probabilities, the following relationship exist:
So, first we need to calculate the probability that none of the 7 lived up to 3.
If the probability that one lived up to 3 years is 0.98861, then the probability than one do not live up to 3 years is 1 - 0.98861
This gives:
The probability that none of the 7 lives up to 3 is:
Substitute this value for P(None) in
---- Approximated
No, it is not unusual if at least 1 lives up to 3.
This is so because the above results, which is 1 shows that it is very likely for at least one of the seven to live up to 3 years
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Answer:
Step-by-step explanation:
To solve an equation for one of its variables do that:
- Underline the variable
- Separate it one side and the other terms on the other side
- Make its coefficient equal to 1
Let us use these steps to solve our question
∵ V = πr²h
→ Underline r²
∴ V = π<u>r²</u>h
→ Take π and h to the other side by dividing both sides by πh
∵
∴
→ The coefficient of r² is 1, so switch the two sides
∴