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vlada-n [284]
3 years ago
13

Problem Solving REAL WORLD 14. 13. Jerome is making prizes for a game at the school fair. He has two bags of different candies,

one with 15 pieces of candy and one with 20 pieces. Every prize will have one kind of candy, the same number of pieces, and the greatest number of pieces possible. How many candies should be in each prize? 2 candies
Mathematics
1 answer:
Artemon [7]3 years ago
6 0

Answer: There are 5 candies of first type and 4 candies of second type.

Step-by-step explanation:

Since we have given that

Number of pieces of candy of first type = 15

Number of pieces of candy of second type = 20

We need to find the greatest number of pieces possible.

So, Greatest number of pieces = H.C.F. of 15 and 20 = 5

So, there are 5 greatest number of pieces possible.

Number of candies of first type in this piece = \dfrac{15}{5}=5

Number of candies of second type in this piece = \dfrac{20}{5}=4

Hence, there are 5 candies of first type and 4 candies of second type.

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