Answer:
a) 0.0821
b) 0.0111
c) 0.0041
Step-by-step explanation:
Exponential distribution:
The exponential probability distribution, with mean m, is described by the following equation:
![f(x) = \lambda e^{-\lambda x}](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Clambda%20e%5E%7B-%5Clambda%20x%7D)
In which
is the decay parameter.
The probability that x is lower or equal to a is given by:
![P(X \leq x) = \int\limits^a_0 {f(x)} \, dx](https://tex.z-dn.net/?f=P%28X%20%5Cleq%20x%29%20%3D%20%5Cint%5Climits%5Ea_0%20%7Bf%28x%29%7D%20%5C%2C%20dx)
Which has the following solution:
![P(X \leq x) = 1 - e^{-\lambda x}](https://tex.z-dn.net/?f=P%28X%20%5Cleq%20x%29%20%3D%201%20-%20e%5E%7B-%5Clambda%20x%7D)
Either it lasts more 5 years or less, or it survives more than 5 years. The sum of the probabilities of these events is decimal 1. So
![P(X \leq 5) + P(X > 5) = 1](https://tex.z-dn.net/?f=P%28X%20%5Cleq%205%29%20%2B%20P%28X%20%3E%205%29%20%3D%201)
In all 3 cases, we want P(X > 5). So
![P(X > 5) = 1 - P(X \leq 5)](https://tex.z-dn.net/?f=P%28X%20%3E%205%29%20%3D%201%20-%20P%28X%20%5Cleq%205%29)
In which
![P(X \leq 5) = 1 - e^{-5\lambda}](https://tex.z-dn.net/?f=P%28X%20%5Cleq%205%29%20%3D%201%20-%20e%5E%7B-5%5Clambda%7D)
(a) lambda=.5
![P(X \leq 5) = 1 - e^{-5*0.5} = 0.9179](https://tex.z-dn.net/?f=P%28X%20%5Cleq%205%29%20%3D%201%20-%20e%5E%7B-5%2A0.5%7D%20%3D%200.9179)
![P(X > 5) = 1 - P(X \leq 5) = 1 - 0.9179 = 0.0821](https://tex.z-dn.net/?f=P%28X%20%3E%205%29%20%3D%201%20-%20P%28X%20%5Cleq%205%29%20%3D%201%20-%200.9179%20%3D%200.0821)
(b) lambda=0.9
![P(X \leq 5) = 1 - e^{-5*0.9} = 0.9889](https://tex.z-dn.net/?f=P%28X%20%5Cleq%205%29%20%3D%201%20-%20e%5E%7B-5%2A0.9%7D%20%3D%200.9889)
![P(X > 5) = 1 - P(X \leq 5) = 1 - 0.9889 = 0.0111](https://tex.z-dn.net/?f=P%28X%20%3E%205%29%20%3D%201%20-%20P%28X%20%5Cleq%205%29%20%3D%201%20-%200.9889%20%3D%200.0111)
(c) lambda=1.1
![P(X \leq 5) = 1 - e^{-5*1.1} = 0.9959](https://tex.z-dn.net/?f=P%28X%20%5Cleq%205%29%20%3D%201%20-%20e%5E%7B-5%2A1.1%7D%20%3D%200.9959)
![P(X > 5) = 1 - P(X \leq 5) = 1 - 0.9959 = 0.0041](https://tex.z-dn.net/?f=P%28X%20%3E%205%29%20%3D%201%20-%20P%28X%20%5Cleq%205%29%20%3D%201%20-%200.9959%20%3D%200.0041)
(21 + 34 + x + 25 + 37 + 22) / 6 = 30
(139 + x) / 6 = 30 .....multiply both sides by 6
139 + x = 30 * 6
139 + x = 180
x = 180 - 139
x = 41......so during week 3, she rode her bike 41 miles
Step 1 : Simplify both sides
-5(6a+21)=-15
(-5)(6a)+(-5)(21)=-15
-30a-105=-15
Step 2 : Add 105 to both sides
-30a-105+105=-15+105
-30a=90
Step 3 : Divide both sides by -30
-30a=90
—————
-30 -30
a = -3
Perimeter = (length+width) x 2
Let w units be the width of the rectangle.
Length of the rectangle = 2w
Perimeter:
(2w+w) x 2 = 60
(3w)2 = 60
6w = 60
w = 10
Area:
2(10) x 10
= 20 x 10
= 200 units