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Yuliya22 [10]
3 years ago
11

Can (5z+3)(-5z-3) result in a difference of squares

Mathematics
1 answer:
castortr0y [4]3 years ago
8 0

Answer:

no, it cannot

Step-by-step explanation:

a difference of square is: a² - b² = (a - b)(a + b)

looking at the expression (5z+3)(-5z-3), we see that it does not fit the criteria of the breakdown of a perfect square, as (-5z-3) has a negative <em>a</em> term (-5z)

if we FOILed (5z+3)(-5z-3) out, we would get:

-25z² - 30z - 9, which is not a difference of squares

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Michaels account overdrafts $75.00. write an absolute value to represent the overdraft
Klio2033 [76]

Overdrafting is when you deposit you're money in a bank account so it could either be +75 or -75 both of them might be correct.

8 0
3 years ago
Choose the correct standard form of the number.
Scrat [10]
Forty and nine thousandths is the same thing as 40.009 in Standard form.
5 0
3 years ago
Urgent Math Help Needed ASAP
Marta_Voda [28]

Answer:

Fourth option: 30 days

Step-by-step explanation:

We three path to complete the project:

Path A:

A1 → A2 → A3

10 days → 8 days → 9 days = 27 days


Path B:

B1 → B2 → B3

2 days → 7 days → 3 days = 12 days


Path C:

C1 → C2 → C3

10 days → 8 days → 12 days = 30 days


Then the duration of the critical path is 30 days, we can't conclude the project until each path has finished

7 0
4 years ago
STEVEN
masha68 [24]

The constant value of $16 will remain unchanged no matter the coefficient of x being the initial deposit

<h3>Linear equations</h3>

These are equations that has a leading degree of 2. The standard linear equation is expressed as:

y = mx + b

If Lauren wrote the equation y = 3x + 16 to represent the amount of money in a bank account that starts with $16 and increases by $3 each week, the constant value of $16 will remain unchanged no matter the coefficient of x being the initial deposit

Learn more on linear function here: brainly.com/question/15602982

#SPJ1

3 0
2 years ago
Ninety six passengers rode a train. Tickets for regular coach seats are $114. Tickets for sleeper car seats are $295. The receip
MrRa [10]
C = amount of folks buying coach tickets
s = amount fo folks buying sleeper car tickets

we know the train had a total of 96 passengers, so, whatever "c" and "s" are
c + s = 96

we know all tickets sold for all 96 passengers was 19994, so, if "c" folks rode coach, each ticket is 114, thus 114*c is  how much money was from couch, or 114c

if "s" folks rode the sleeper car, we know each ticket is 295 each, so 295*s is how much money was from the sleeper car

we also know, the total for all tickets is 19994

thus    114c + 295s = 19994

thus   \bf \begin{cases}&#10;c+s=96\implies \boxed{s}=96-c\\&#10;114c+295s = 19994\\&#10;----------\\&#10;114c+295\left( \boxed{96-c} \right)=19994&#10;\end{cases}

solve for "s", to see how many folks rode coach

what about the sleeper car? well, s = 96 - c
5 0
3 years ago
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