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3 years ago

7

Is (x+a) (x+b) the same thing as x(a+x+b)?

2 answers:

VMariaS [17]3 years ago

6 0

No, I dont believe its the same thing because I remember doimg those equations in high school and they were different

Rufina [12.5K]3 years ago

3 0

Not at all are they the same in my opinion.

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2 years ago

Circles are described below by the coordinates of their centers, C, and one point on their circumference, A. Determine an equati

Art [367]

Using the given center and point at the circumference, the equation of the circles are:

a) $(x - 5)^2 + (y - 2)^2 = 100$

b) $(x + 2)^2 + (y + 5)^2 = 169$

c) $(x - 5)^2 + (y + 1)^2 = 65$

<h3>What is the equation of a circle?</h3>

The equation of a circle of radius r and center $(x_0,y_0)$ is given by:

$(x - x_0)^2 + (y - y_0)^2 = r^2$

Item a:

Center C(5,2), hence $x_0 = 5, y_0 = 2$ .

The point at the circumference is A(11,10), hence:

$(x - 5)^2 + (y - 2)^2 = r^2$

$(11 - 5)^2 + (10 - 2)^2 = r^2$

$r^2 = 100$

Hence:

$(x - 5)^2 + (y - 2)^2 = 100$

Item b:

Center C(-2,-5), hence $x_0 = -2, y_0 = -5$ .

The point at the circumference is A(3,-17), hence:

$(x + 2)^2 + (y + 5)^2 = r^2$

$(3 + 2)^2 + (-17 - 5)^2 = r^2$

$r^2 = 169$

Hence:

$(x + 2)^2 + (y + 5)^2 = 169$

Item c:

Center C(5,-1), hence $x_0 = 5, y_0 = -1$ .

The point at the circumference is A(-2,-5), hence:

$(x - 5)^2 + (y + 1)^2 = r^2$

$(-2 - 5)^2 + (-5 + 1)^2 = r^2$

$r^2 = 65$

Hence:

$(x - 5)^2 + (y + 1)^2 = 65$

You can learn more about equation of a circle at brainly.com/question/24307696

4 0

2 years ago

timurjin [86]

Answer:

Step-by-step explanation:

To be parallel the slopes must be equal

4x-3y=15

3y=4x-15

y=(4x-15)/3

so m=4/3

Only line D. has a slope of 4/3

7 0

3 years ago

Read 2 more answers