Answer:
Step-by-step explanation:
2(6x² - 3) = 11x² - x
2*6x² - 2*3 = 11x² - x
12x² - 6 = 11x² -x
Subtract 11x² from both sides
12x² - 11x² - 6 = -x
x² - 6 = -x
x² + x - 6= 0
Sum =1
Product = -6
Factors = 3 , (-2) { 3*(-2) = -6 & 3 +(-2) = 1}
x² + 3x - 2x - 6 = 0
x(x + 3) - 2(x + 3)= 0
(x +3)(x - 2) = 0
Answer:
The player with the most runs had a rush of 1,240 yards
Step-by-step explanation:
In this question, we are asked to calculate the number of yards that was rushed by one of two person given their combined run and an extra information.
Firstly, let the person that had the smaller number of rush have a rush of x rushes. The second person has a rush of 4 times the other. This makes a number of 4x rushes
By adding both together, we have a total of 1550 yards
Mathematically, this means that x + 4x = 1550
5x = 1550
x = 1550/5 = 310 rushes
The second player had a rush of 4x and that is 4 * 310 = 1,240 rushes
Answer:
C.) 35.08 is the answer
Step-by-step explanation:
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Answer:
Step-by-step explanation:
Set up an equation, where x is the number of gallons of 60% antifreeze solution.
Represent the percentages of antifreeze with decimal values.
0.6x + 0.3(80) = 0.5(x + 80)
Simplify and solve for x:
0.6x + 24 = 0.5x + 40
0.1x = 16
x = 160
So, you have to mix 160 gallons of a 60% antifreeze solution
