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Mekhanik [1.2K]
3 years ago
5

Find the exact value of sec30°.

Mathematics
2 answers:
vlabodo [156]3 years ago
5 0

Answer:

The exact form is, 2 square root 3/3.

The decimal form is, 1.1547.

julsineya [31]3 years ago
3 0

Decimal Form:

1.15470053

…

Step-by-step explanation:

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Ms. Bloom brought 4 packs of treats for Halloween. She gave away 2 1/9 packs of treats to her class and gave away 5/9 packs of t
Eddi Din [679]

Answer: 1 1/3 packs of treats


Step-by-step explanation:

2 1/9 + 5/9 = 2 6/9, which can be simplified to 2 2/3.

We subtract 2 2/3 from 4, giving us 1 1/3

8 0
3 years ago
True or false. For a trigonometric function, y=f(x) then x=F-1(y). Explain your answer.
sergejj [24]
False if y=f(x) then x= inverse of f(x) or f^-1(x)
3 0
3 years ago
Read 2 more answers
Which equation represents a circle that contains the point (-5,-3) and has a center at (-2,1)
MatroZZZ [7]

Answer:

The equation of circle is:

Solution:

The general form of equation is given as:

Where, "r" is radius of circle and (a, b) is center of circle

Given that center at (-2, 1)

a = -2 and b = 1

Substitute (a , b) = (-2, 1) and (x, y) = (-5, -3) in general equation

Substitute r = 5 and (a, b) = (-2, 1) in general equation

Thus the equation of circle is found

4 0
3 years ago
manuel deposits $10000 for 12 yr in an account paying 4% compounded annually.He then puts this total amount on deposit in anothe
Naddik [55]
\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$10000\\
r=rate\to 4\%\to \frac{4}{100}\to &0.04\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &12
\end{cases}
\\\\\\
A=10000\left(1+\frac{0.04}{1}\right)^{1\cdot 12}\implies A=1000(1.04)^{12}\\\\\\ A\approx 16010.32

he then turns around and grabs that money and sticks it for another 9 years,

\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
~~
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$16010.32\\
r=rate\to 5\%\to \frac{5}{100}\to &0.05\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{semi-annually, thus twice}
\end{array}\to &2\\
t=years\to &9
\end{cases}
\\\\\\
A=16010.32\left(1+\frac{0.05}{2}\right)^{2\cdot 9}\implies A=16010.32(1.025)^{18}
\\\\\\
A\approx 24970.64

add both amounts, and that's how much is for the whole 21 years.
6 0
4 years ago
Can someone help with this question
eduard
Now, as you can see - these are ordered pairs. So, in order to find possible solutions - we have to plot this inequality on a graph! 

So, let's do this. I am using GeoGebra in order to graph this inequality. 

Alright, so... Now I'm going to go through, and look at each ordered pair and see if they are covered by the shaded region!

Answer A: False
Answer B: False
Answer C: True
Answer D: True
Answer E: True
Answer F: True

Hopefully, this helps you! =)
7 0
4 years ago
Read 2 more answers
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