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nikitadnepr [17]
3 years ago
7

Mr grain left for work at 7:15 am. twenty five mintutes later he aririved at his work. what time did mr giarmo arrive at his

Mathematics
1 answer:
Genrish500 [490]3 years ago
5 0
25 minutes (0:25) added to 7:15.

7:15 + 0:25 = 7:40
Also expressible as 15+25

He arrived at 7:40AM.
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What is the answer of 603 x 42 , this question is multiply , it’s of my brother who is just in g-4 …… pls help if you know but t
satela [25.4K]

Answer:

<h2>25326</h2>

Step-by-step explanation:

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4 0
3 years ago
Solve the simultaneous equation<br> X+3y=13<br> X-y=5
Andru [333]

Answer:

x = 7

y = 2

Step-by-step explanation:

In the above question, we are given 2 equations which are simultaneous. To solve this equation, we have to find the values of x and y

x + 3y = 13 ........ Equation 1

x - y = 5...........Equation 2

From Equation 2,

x = 5 + y

Substitute 5 + y for x in Equation 1

x + 3y = 13 ........ Equation 1

5 + y + 3y = 13

5 + 4y = 13

4y = 13 - 5

4y = 8

y = 8/4

y = 2

Since y = 2, substitute , 2 for y in Equation 2

x - y = 5...........Equation 2

x - 2 = 5

x = 5 + 2

x = 7

Therefore, x = 7 and y = 2

5 0
3 years ago
Write an equation of the line that passes through (18, 2) and is parallel to the line 3y−x=−12
miskamm [114]

keeping in mind that parallel lines have the same exact slope, hmmmm what's the slope of the line above anyway?

\bf 3y-x=-12\implies 3y=x-12\implies y=\cfrac{x-12}{3}\implies y = \cfrac{x}{3}-\cfrac{12}{3} \\\\\\ y = \stackrel{\stackrel{m}{\downarrow }}{\cfrac{1}{3}}x-4\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}

so we're really looking for the equation of a line whose slope is 1/3 and runs through (18,2)

\bf (\stackrel{x_1}{18}~,~\stackrel{y_1}{2})~\hspace{10em} \stackrel{slope}{m}\implies \cfrac{1}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{2}=\stackrel{m}{\cfrac{1}{3}}(x-\stackrel{x_1}{18}) \\\\\\ y-2=\cfrac{1}{3}x-6\implies y=\cfrac{1}{3}x-4

3 0
3 years ago
The answer appears incorrect, please help me correct it :)
UNO [17]

Every line on the graph is 1/2 unit.

When y = 0, x would be -0.25 and 1.25

When y = 2, x would be -0.5 and 1.5

4 0
3 years ago
at maximum speed, an airplane travels 1720 miles against th wind in 5 hours. Flying with the wind, the plane can travel the same
iragen [17]

Answer:

x = 387

Step-by-step explanation:

The wind acts in the opposite direction to the plane when the time is longer.

The wind acts in the same direction as the plane when the time is shorter.

Equation

d = r*t

Givens

  • d = 1720
  • x = plane's speed
  • y = wind speed
  • t1 = 5 hours
  • t2 = 4 hours.

Substitution

  • d = (x + y) * t
  • 1720 = (x + y) * 4
  • 1720 = (x - y) * 5

Since the two distances are the same, you can equate the right hand sides.

  • (x + y) * 4 = (x - y)*5              Remove the brackets.
  • 4x + 4y = 5x - 5y                  Add 5y to both sides
  • 4x + 4y + 5y = 5x - 5y + 5y  Combine all the terms.
  • 4x + 9y = 5x                          Subtract 4x from both sides
  • 9y + 4x - 4x = 5x - 4x           Combine
  • 9y = x

Now use one of the given equations with the distance

  • 1720 = (x + y)*4           Substitute 9y for x
  • 1720 = (9y + y) *  4      Combine
  • 1720 = 10y * 4             Multiply the right
  • 1720 = 40y                  Divide by 40
  • 1720/40 = 40y/40      Do the division
  • 43 = y                          y = wind speek
  • 9y = x                          x = 9*y  
  • 9*43 = x
  • x = 387 miles per hour.
4 0
4 years ago
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