Answer:
quadrant ll
Step-by-step explanation:
A point on the y-axis will always have an x-coordinate of zero. Instructions: In the figure above, the point with coordinates (4,2) is located in quadrant I. The point with coordinates (-3,4) is located in quadrant II.
I like the substitution method. Which is when you make one equation equal only x or y and plug it into the other equation)
There is also the graphing method. If you graphed it, it might not be quite as accurate (at least on hand, on computer you would be pretty exact)
Then there is the elimination method. You multiply one of the equations by a coefficient so that you can eliminate x or y from the equation.
Answer:
So, the first three nonzero terms in the Maclaurin series are:

Step-by-step explanation:
From exercise we have the next function y = 6 sec(3x).
We know that Maclaurin series for the function sec x, have the following form:

So, for the given function y = 6 sec(3x), we get:

So, the first three nonzero terms in the Maclaurin series are:

2 quarts- 8 tablespoons
12 quarts- 8 x 6 = 48 tablespoons
We will use the property :
sum of interior angles on same side of transversal =180
(8x-14) + (2x+54)=180
10x+40=180
10x=140
x=14