Answer:
2
Step-by-step explanation
I gave been doing massive research on this topic and have been trying to complete it. If my research is right the answer will be 2.
Since length of diagonal ( 
) is less than diameter of circle ( 11 cm ) , Therefore , the square will fit inside the circle without touching the edge of the circle.
<u>Step-by-step explanation:</u>
Here we have , A circle has diameter of 11 cm A square has side length of 7 cm . Use Pythagoras’ Theorem to show that the square will fit inside the circle without touching the edge of the circle . Let's find out:
We know the concept that for any square to fit inside the circle without touching the edge of circle , diagonal of square must be less than diameter of circle . Let's find out length of diagonal by using Pythagoras Theorem :
For a square , 
⇒ 
⇒ 
⇒ 
⇒
Since length of diagonal ( ) is less than diameter of circle ( 11 cm ) , Therefore , the square will fit inside the circle without ruching the edge of the circle.
Answer:
Step-by-step explanation:
total metre = 10m
If one piece is 4m then 2m more then that = 4 + 2 = 6m
So total = 4 + 6 = 10m
- Answer:-The multiplicative rate of change for the exponential function =3. Explanation:- The exponential function is given by y=Ab^x. , where A
Step-by-step explanation:
Answer:
Step-by-step explanation:
A]
Both have the same surface area. The numbers are just rearranged.
B]
Is the correct answer.
The surface area of the first one is 2*8*5 + 2*8*6 + 2*5*6 = 236
The surface area of the second is 2*10*8 + 2*10*3 + 2*8*3 = 244
C]
Another rearrangement. Not the answer.
D]
