Triangle ABC is a right triangle. Angle B is a right angle and m<A=33°. What is m<C
1 answer:
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Lagrange multipliers:
(if 
)
(if )
(if 
)
In the first octant, we assume
, so we can ignore the caveats above. Now,
so that the only critical point in the region of interest is (1, 2, 2), for which we get a maximum value of
.
We also need to check the boundary of the region, i.e. the intersection of
with the three coordinate axes. But in each case, we would end up setting at least one of the variables to 0, which would force 
, so the point we found is the only extremum.
In the first octant, we assume
so that the only critical point in the region of interest is (1, 2, 2), for which we get a maximum value of
We also need to check the boundary of the region, i.e. the intersection of
Answer:
y=6x+1
Step-by-step explanation:
First you must find the slope of the two points...
which then would equal 6
Then you take the slope and put into point-slope form
(y-y1)=m(x-x1)...take one of the points that is given and plug it into this formula.
so I used (-3,19).
(y-19)=6(x--3)
I would then get y-19=6x+18
Add 19 to both sides and you will get y=6x+1