Laugh out loud a pun isn't it
Answer:
1/4
Step-by-step explanation:
The answer to this question is the amount of blue gummy bears over the total amount of gummy bears. This is 15/60 or 1/4.
Answer:
Keenan's z-score was of 0.61.
Rachel's z-score was of 0.81.
Step-by-step explanation:
Z-score:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Keenan scored 80 points on an exam that had a mean score of 77 points and a standard deviation of 4.9 points.
This means that 
So



Keenan's z-score was of 0.61.
Rachel scored 78 points on an exam that had a mean score of 75 points and a standard deviation of 3.7 points.
This means that
. So



Rachel's z-score was of 0.81.
Answer:
5/48
Step-by-step explanation:
probabilty= 5/12 * 3/12
Answer:
Reject Null Hypothesis given that P-value < ∝
Step-by-step explanation:
Applying the Five ( 5 ) step model and assuming ∝ = 0.05
First step : determine the Null hypothesis
H0 : Age and support for Anti-smoking = independent
Second step : Determine the alternate hypothesis
Ha : Age and support for Anti-smoking ≠ independent
Thirdly : Identify significance level ( ∝ ) = 0.05
4th step : Calculate the Test statistic and P-value
Chi-squared test = 36.1429 using excel function
P-value = 1 - CHISQ.DIST(36.1429, 1, TRUE) < 0.0001
finally : we can conclude that Age and support for Anti -smoking are not Independent hence we Reject The Null hypothesis. Given that
P-value < ∝