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3 years ago

But what line has the same slope as y=1/2x-3?

Mathematics

1 answer:

hodyreva [135]3 years ago

6 0

Answer: Any line with 1/2x

Step-by-step explanation: Since 1/2x is the slope of y=1/2x-3, any equation with 1/2x will have the same slope. The constant doesn't matter since that's just the y-intercept.

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Whats the answer 6+1

Sergeeva-Olga [200]

Answer:

Step-by-step explanation:

Add 1 to six and u get seven.

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3 years ago

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Sub :- Linear Equations

vesna_86 [32]

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The value of x is 1 & y is 2 (a).

Steps are attached.

______

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2 years ago

Use induction to show that 12 + 22 + 32 + ... + n2 = n(n+1)(2n+1)/6, for all n > 1.

dlinn [17]

Answer with Step-by-step explanation:

Let $P(n)=1^2+2^2+3^2+.....+n^2=\frac{n(n+1)(2n+1)}{6}$

Substitute n=2

Then $P(2)=1+2^2=5$

$P(2)=\frac{2(2+1)(4+1)}{6}=5$

Hence, P(n) is true for n=2

Suppose that P(n) is true for n=k >1

$P(k)=1^2+2^2+3^2+...+k^2=\frac{k(k+1)(2k+1)}{6}$

Now, we shall prove that p(n) is true for n=k+1

$P(k+1)=1^2+2^2+3^2+...+k^2+(k+1)^2=\frac{(k+1)(k+2)(2k+3)}{6}$

LHS

$P(k+1)=1^2+2^2+3^2+.....+k^2+(k+1)^2$

Substitute the value of P(k)

$P(k+)=\frac{k(k+1)(2k+1)}{6}+(k+1)^2$

$P(k+1)=(k+1)(\frac{k(2k+1}{6})+k+1)$

$P(k+1)=(k+1)(\frac{2k^2+k+6k+6}{6})$

$P(k+1)=(k+1)(\frac{2k^2+7k+6}{6})$

$P(k+1)=(k+1)(\frac{2k^2+4k+3k+6}{6})$

$P(k+1)=\frac{(k+1)(k+2)(2k+3)}{6}$

LHS=RHS

Hence, P(n) is true for all n >1.

Hence, proved

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3 years ago

A shopping channel shipped 467,023 packages last year. What is a reasonable estimate of number of packages shipped?Explain.

kirza4 [7]

470,000 because when you round the number up, you get 470,000. it is reasonable

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You went to lunch with your friend and the bill was $19 your lunch is three dollars more than your friends how much was your fri

ad-work [718]

Answer:

Let x = cost of your friend's lunch.

x + x + 3 = 19

x= 8

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3 years ago

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