3 years ago

Planes A and B intersect in line s. If point V is a point on line s, then it lies on:

1 answer:

7 0

<span>Planes A and B intersect in line s. If point V is a point on line s, then it lies on b</span><span>oth plane A and B
</span>

You might be interested in

The point LaTeX: \left(-1,\:5\right)( − 1 , 5 ) is the solution for the following system of equations

balu736 [363]

I think right is correct ( - 1, 5 )

4 0

3 years ago

Cant figure out the improper and mixed

Ymorist [56]

The mixed number for this diagram would be: 4 5/6
The improper fraction would be: 29/6
That’s going off of the whole diagram.

6 0

3 years ago

Find the area of Region IV for this figure. A) 16 square units B) 64 square units C) 32 square units D) 36 square units

mamaluj [8]

The answer is D 8 x 2

4 0

3 years ago

Which symbol correctly compares the fractions below?<br> 1/8 ? 1/2

antoniya [11.8K]

Answer:

Step-by-step explanation:

1/2 = 4/8

=> 1/8 < 4/8

=> 1/8 < 1/2

6 0

3 years ago

Can someone help me with this problem

Alex_Xolod [135]

Answer:

Step-by-step explanation:

The formula of a distance between two points:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

A(-3, 0) , B(3, 2)

$AB=\sqrt{(3-(-3))^2+(2-0)^2}=\sqrt{6^2+2^2}=\sqrt{36+4}=\sqrt{40}=\sqrt{4\cdot10}=\sqrt4\cdot\sqrt{10}=2\sqrt{10}$

A(-3, 0), D(-2, -3)

$AD=\sqrt{(-2-(-3))^2+(-3-0)^2}=\sqrt{1^2+(-3)^2}=\sqrt{1+9}=\sqrt{10}$

AB = CD and AD = BC

The area of a rectangle:

$A=(AB)(AD)$

Substitute:

$A=(2\sqrt{10})(\sqrt{10})=(2)(10)=20$

The perimeter of a rectangle:

$P=2(AB+AD)$

Substitute:

$P=2(2\sqrt{10}+\sqrt{10})=2(3\sqrt{10})=6\sqrt{10}$

4 0

3 years ago