Ask question

Ask question

All categories

2 years ago

11

Planes A and B intersect in line s. If point V is a point on line s, then it lies on:

1 answer:

kaheart [24]2 years ago

7 0

<span>Planes A and B intersect in line s. If point V is a point on line s, then it lies on b</span><span>oth plane A and B
</span>

You might be interested in

Math assignment y’all help ya girl

lisov135 [29]

(9-15)/(-2+4)= -6/2 = -3

-3 is the slope

5 0

2 years ago

Please please help me on this question

Delvig [45]

-7x^2 - 6x^2 + 3x + 5x - 5 + 2
-13x^2 + 8x - 3

5 0

3 years ago

If you help me with this fast I will brain you.<br> Thanks.

irakobra [83]

Answer:

-2 and -6 is the correct answer

5 0

2 years ago

tia_tia [17]

Answer:

$8-6i$

Step-by-step explanation:

Multiply out $(3-i)^2$ in order to find out which expression it is equivalent to.

1) Since the whole quantity is squared, write it out as $(3-i)(3-i)$ .

$(3-i)^2\\(3-i)(3-i)$

2) Multiply binomials by using the FOIL method. Multiply the terms that are listed first in each binomial, then the ones that are listed outermost when looking at both binomials, then innermost, and finally the last terms listed in each binomial. Simplify and combine like terms.

$(3-i)(3-i)\\9 - 3i - 3i + i^2$

$9 - 6i + i^2$

3) $i = \sqrt{-1}$ , so $i ^2$ must be $(\sqrt{-1} )(\sqrt{-1})$ . Thus, $i^2$ is equivalent to -1. Knowing this, simplify and combine like terms.

$9 - 6i + ((-\sqrt{1} )(\sqrt{-1} ))$

$9 - 6i -1\\8 - 6i$

Thus, it is equivalent to $8 - 6i$ .

6 0

3 years ago

I NEED HELP!! please show all work

PtichkaEL [24]

Take the logarithm of both sides. The base of the logarithm doesn't matter.

$4^{5x} = 3^{x-2}$

$\implies \log 4^{5x} = \log 3^{x-2}$

Drop the exponents:

$\implies 5x \log 4 = (x-2) \log 3$

Expand the right side:

$\implies 5x \log 4 = x \log 3 - 2 \log 3$

Move the terms containing <em>x</em> to the left side and factor out <em>x</em> :

$\implies 5x \log 4 - x \log 3 = - 2 \log 3$

$\implies x (5 \log 4 - \log 3) = - 2 \log 3$

Solve for <em>x</em> by dividing boths ides by 5 log(4) - log(3) :

$\implies \boxed{x = -\dfrac{ 2 \log 3 }{ 5 \log 4 - \log 3 }}$

You can stop there, or continue simplifying the solution by using properties of logarithms:

$\implies x = -\dfrac{ \log 3^2 }{ \log 4^5 - \log 3 }$

$\implies x = -\dfrac{ \log 9 }{ \log 1024 - \log 3 }$

$\implies \boxed{x = -\dfrac{ \log 9 }{ \log \frac{1024}3 }}$

You can condense the solution further using the change-of-base identity,

$\implies \boxed{x = -\log_{\frac{1024}3}9}$

5 0

2 years ago