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3 years ago

Write the equation of a line that is parallel to y = 7x +13 that passes through the point (28, 8).

Mathematics

1 answer:

navik [9.2K]3 years ago

7 0

Answer:

y=7x-188

Step-by-step explanation:

We know that this line must have a slope of 7, because this line is parallel to y=7x+13

We must use the point slope formula: y- $y_{1}$ = m(x- $x_{1}$ )

Next, we will plug in the point (28,8) for $y_{1}$ and $x_{1}$ , and 7 in for m

y-8=7(x-28)

Solve the equation, first by distributing the 7

y-8=7x-196

Add the 8 over

y=7x-188

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3 years ago

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Answer:

Step-by-step explanation:

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4 years ago

If f(x)= 2(3x²-2x+2). Find: A) f(x+1) B) f(3) C) f(y-2)

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I hope this helps :)

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