Write the equation of a line that is parallel to y = 7x +13 that passes through the point (28, 8).
1 answer:
Answer:
y=7x-188
Step-by-step explanation:
We know that this line must have a slope of 7, because this line is parallel to y=7x+13
We must use the point slope formula: y-= m(x-
)
Next, we will plug in the point (28,8) for and
, and 7 in for m
y-8=7(x-28)
Solve the equation, first by distributing the 7
y-8=7x-196
Add the 8 over
y=7x-188
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the perimeter of the triangle=14.38
The coordinates of the triangle (4,1),(2,5),(1,-1);
In geometry, the perimeter of a shape is defined as the total length of its boundary.
The perimeter of the triangle is the sum of all the sides of the triangle =a+b+c (assuming a,b, and c are the sides of the triangle)
By using the distances formula find the length of the sides of the triangle:√[(x₂ - x₁)² + (y₂ - y₁)²],
where (x₁,y₁),(x₂,y₂) are the coordinates ,
a=√[(4 - 2)² + (1- 5)²] = =4.7
b=√[(2 -1)² + (5 -(-1))²]==6.08
c=√[(1 -4)² + ((-1)-1)²]==3.60
the perimeter of the triangle=a+b+c=4.7+6.08+3.60=14.38
hence ,perimeter of the triangle=14.38
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