Answer:
pls translate to English so we can help
Answer: str[0].toUpperCase();
Explanation:
str[0] is pointing to the first character of the entire string and the code str[0].toUpperCase() will convert the characters to upper case if they are in lowercase and will remain unchanged if they are already in upper case.
Answer:
Explanation:
The code does not fail on the first step since 1900 divided by 4 is actually 475 and has no remainder, meaning that it should return True. The code won't work because the if statements need to be nested in a different format. The correct algorithm would be the following, which can also be seen in the picture attached below that if we input 1900 it would output is not a leap year as it fails on the division by 400 which gives a remainder of 0.75
input_year = int(input())
if input_year % 4 == 0:
if input_year % 100 == 0:
if input_year % 400 == 0:
print(input_year, "is a leap year")
else:
print(input_year, "- not a leap year")
else:
print(input_year, "is a leap year")
else:
print(input_year, "- not a leap year")
First you must pick what application you want to do your document on and chose how you want to map out your document.
Answer:
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