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3 years ago

Given h(x) = 2x + 2, find

Mathematics

1 answer:

Svetlanka [38]3 years ago

5 0

2x + 2
2(x+1)

where’s the value of X and the given of g(x)=???

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F(x)= 2x +6 , vertical shrink by a factor of 1/2

Andrew [12]

Answer:

g(x) = x+3.

Step-by-step explanation:

i hope this helps :D

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3 years ago

80 times 1.5 that’s all

Evgesh-ka [11]

What?

explanation: ..

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3 years ago

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Frank is going to the airport. It is 11:43 AM right now. Frank's flight will depart in 2 hours 40 minutes. What is the departure

Stels [109]

Ok it would be 1:23 p.m. i think

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3 years ago

A function f is differentiable for all values of x in [0,6], and the graph with equation y=f(x) has a local minimum point at (2,

MrRa [10]

Step-by-step explanation:

The slope of tangent line at a max or a minimum is 0,.

So using point slope formula.

$y - 4 = 0(x - 2)$

$y = 4$

Is the equation of a tangent line. This means we have a horizontal line at y= 4. Horizontal lines have a slope of 0.

4 0

2 years ago

Answer correct you get brainliest answer

zloy xaker [14]

Answer:

$y = {x}^{2} - 2$

Or if you want with the value of h too.

$y = {(x - 0)}^{2} - 2$

Step-by-step explanation:

$y = a {(x - h)}^{2} + k$

Find the value of h and k by using the formula.

$h = - \frac{b}{2a} \\ k = \frac{4ac - {b}^{2} }{4a}$

From y = x²-2

$a = 1 \\ b = 0 \\ c = - 2$

Substitute these values in the formula.

$h = - \frac{0}{2(1)} \\ h = 0$

Therefore, h = 0.

$k = \frac{4(1)( - 2) - {0}^{2} }{4(1)} \\ k = \frac{ - 8}{4} \\ k = - 2$

Therefore, k = - 2.

From the vertex form, the vertex is at (h, k) = (0,-2). Substitute h = 0, a = 1 and k = -2 in the equation.

$y = a {(x - h)}^{2} + k \\ y = 1 {(x - 0)}^{2} - 2 \\ y = {(x)}^{2} - 2 \\ y = {x}^{2} - 2$

These type of equation where b = 0 can also be both standard and vertex form.

4 0

3 years ago