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3 years ago

What is the exact radian measure of an angle of 132

1 answer:

6 0

Since we know that in π radians there are 180°, thus how many radians in 132°?

$\bf \begin{array}{ccll}
de grees&radians\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
180&\pi \\
132&x
\end{array}\implies \cfrac{180}{132}=\cfrac{\pi }{x}\implies x=\cfrac{132\cdot \pi }{180}\implies \stackrel{simplified}{\cfrac{11\pi }{15}}$

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joe puts $790.00 into a savings account that pays 5.5% simple interest. he leaves the money in his account for two years.

Dmitrij [34]

Answer: $879.29

Step-by-step explanation:

790(1.055)^2

790(1.113025)

= 879.28975

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3 years ago

First the first 4 term for 4n-5

likoan [24]

Answer:

-1, 3, 7, 11

Step-by-step explanation:

First, let's find term 1. To find this term, we need to replace n with 1 - what is 4(1) - 5? Well, that's just 4 - 5, or -1. So, our first term is -1. Next, we'll find our second term. To do this, we'll replace n with 2. 4(2) = 8, and then 8 - 5 is equal to 3, so our second term is 3. Let's now find the third term by replacing n with the number 3. 4(3) - 5 is equal to 12 - 5, or 7. So, 7 is our third term. Finally, we'll find the fourth term. 4(4) is equal to 16, and 16 - 5 is equal to 11. So, the fourth and final term is equal to 11.

Hopefully that's helpful! :)

5 0

2 years ago

Read 2 more answers

If 3y-x=-7 , what is the value of (2^x)/(8^y)

Travka [436]

Answer:

22=-7

Step-by-step explanation:

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3 years ago

A local company makes a candy that is supposed to weigh 1.00 ounces. A random sample of 25 pieces of candy produces a mean of 0.

AysviL [449]

Answer:

$n=(\frac{2.58(0.004)}{0.001})^2 =106.50 \approx 107$

So the answer for this case would be n=107 rounded up to the nearest integer

Step-by-step explanation:

Information given

$\bar X= 0.996$ the sample mean

$s=0.004$ the sample deviation

$n =25$ the sample size

Solution to the problem

The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (a)

And on this case we have that ME =0.001 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

We can use as estimator of the real population deviation the sample deviation for this case $\hat \sigma = s$ / The critical value for 99% of confidence interval is given by $z_{\alpha/2}=2.58$ , replacing into formula (b) we got:

$n=(\frac{2.58(0.004)}{0.001})^2 =106.50 \approx 107$

So the answer for this case would be n=107 rounded up to the nearest integer

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3 years ago

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liubo4ka [24]

Answer:

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