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3 years ago

Luke ran 3.5 miles in January. How many miles did Luke run in January?

Mathematics

2 answers:

Aneli [31]3 years ago

7 0

Answer:

if Luke has ran 3.5 miles in January, he ran 3.5 miles in January.

but if you mean he ran 3.5 every day in January, he ran 108.5 miles in January.

Step-by-step explanation:

if you get the amount of days in January, that is 31.

so now get the amount of miles he ran (3.5) and the amount of days in January(31) and divide them. 3.5 divided by 31 = 108.5 miles

~~~108 miles~~~

blsea [12.9K]3 years ago

6 0

Answer:

Step-by-step explanation:

3.5 miles

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2 years ago

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3 years ago

Five years ago, Victor was twice as old as his daughter Anika. In 10 years, the sum of their ages will equal 90. Find their ages

frozen [14]

Answer: 45 and 25

Step-by-step explanation:

Given

Five years ago victor was twice as old as his daughter

Suppose the current age of victor and his daughter are x and y

For five years ago

$\Rightarrow (y-5)=2(x-5)\\\Rightarrow y-5=2x-10\\\Rightarrow y=2x-5\\\Rightarrow 2x-y=5\quad \ldots(i)$

In 10 years sum of their ages is 90

$\Rightarrow (y+10)+(x+10)=90\\\Rightarrow x+y=70\quad \ldots(ii)$

On solving (i) and (ii) we get

$\Rightarrow x=25,y=45$

So, the current age of victor is 45 and his daughter is 25

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2 years ago

Recursive formula for 26, 24, 22, 20

dexar [7]

Answer:

a_n = 28-2n

Step-by-step explanation:

Given sequence is:

26,24,22,20

We can see that the difference between consecutive terms is same so the sequence is an arithmetic sequence

The standard formula for arithmetic sequence is:

$a_n = a_1+(n-1)d$

Here,

a_n is the nth term

a_1 is the first term

and d is the common difference

So,

d = 24-26

= -2

a_1 = 26

Putting the values of d and a_1

$a_n = 26 + (n-1)(-2)\\a_n = 26-2n+2\\a_n = 28-2n$

Hence, the recursive formula for given sequence is: a_n = 28-2n ..

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3 years ago