So when solving this you are going to have to solve the equation.
Okay so first thing we need to do is simplify both sides of your equation so:
3x−5=<span>2x+8+x
</span>Simplifying process:
<span><span><span>3x</span>+</span>−5</span>=<span><span><span>2x</span>+8</span>+<span>x
</span></span><span>Combine Like Terms </span>⇒ 3x−5=<span>(2x+x)+(8)
</span><span><span>3x</span>−5</span>=<span><span>3x</span>+<span>8
</span></span><span><span>3x</span>−5</span>=<span><span>3x</span>+<span>8
</span></span>Second thing we are now going to do is s<span>ubtract 3x from both sides<span> so:
</span></span><span><span><span>3x</span>−5</span>−<span>3x</span></span>=<span><span><span>3x</span>+8</span>−<span>3<span>x
</span></span></span><span>−5</span>=<span>8
</span>Final step is to add 5 to both sides:
−5+5=<span>8+5
</span>0=<span>13
</span>The answer to your question is "<span>There are no solutions"</span>
2 and 1/5 is your answer.
decimal form=2.2
Your answer is going to be Letter B
Answer:
I think its B
Step-by-step explanation:
Hope this helps:)
Answer:
The probability that a defective rod can be salvaged = 0.50
Step-by-step explanation:
Given that:
A machine shop produces heavy duty high endurance 20-inch rods
On occasion, the machine malfunctions and produces a groove or a chisel cut mark somewhere on the rod.
If such defective rods can be cut so that there is at least 15 consecutive inches without a groove.
Then; The defective rod can be salvaged if the groove lies on the rod between 0 and 5 inches i.e ( 20 - 15 )inches
Now:
P(X ≤ 5) = 
= 0.25
P(X ≥ 15) =
= 0.25
The probability that a defective rod can be salvaged = P(X ≤ 5) + P(X ≥ 15)
= 0.25+0.25
= 0.50
∴ The probability that a defective rod can be salvaged = 0.50
