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AleksandrR [38]
3 years ago
7

How much does 73 go into 39?

Mathematics
1 answer:
Deffense [45]3 years ago
6 0
.53424657534246575342465753424658

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Find the sum.178,399.2+45.38
kap26 [50]
178444.58 It is a matter of how you arrange your decimal place so while adding make sure the 3 in the second number is under the 2 in the first number.

8 0
3 years ago
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Classrooms on one side of the science building are all numbered with consecutive odd integers. If the first​ room, the room with
liubo4ka [24]

Answer:

The sum of the first five classroom numbers in a row is 5k + 20

Step-by-step explanation:

Since the smallest classroom​ number on the side of the building is numbered k​ and each consecutive odd integer is separated by a difference of  

2.

Therefore:  

k is the first class room.

k +  2  is the second class room.

k +  4  is the third class room.

k + 6 is the third class room.

k + 8 is the fifth class room.

The sum of the five consecutive class rooms are given as:

k + (k + 2) + (k + 4) + (k + 6) + (k + 8)

collecting alike terms we get

=  k + k + k + k + k + 2 + 4 + 6 + 8

= 5k + 20

Therefore, The sum of the first five classroom numbers in a row is 5k + 20.

8 0
3 years ago
Open a bank account make a deposit $150
jeka57 [31]
Don’t have that much money buddy
4 0
3 years ago
You get GPS units from two manufacturers, A and B. You get 43% of your units from A and 57% of your units from B. In the past, 2
defon

Answer:

0.5015 = 50.15% probability that it came from manufacturer A.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Defective

Event B: From manufacturer A.

Probability a unit is defective:

2% of 43%(from manufacturer A)

1.5% of 57%(from manufacturer B). So

P(A) = 0.02*0.43 + 0.015*0.57 = 0.01715

Probability a unit is defective and from manufacturer A:

2% of 43%. So

P(A \cap B) = 0.02*0.43 = 0.0086

What is the probability that it came from manufacturer A?

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.0086}{0.01715} = 0.5015

0.5015 = 50.15% probability that it came from manufacturer A.

4 0
2 years ago
Which equation has no soultion
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Answer:

i dont get your question love

Step-by-step explanation:

6 0
3 years ago
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