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jekas [21]
3 years ago
13

I need help!! Describe how to determine the average rate of change between x = 1 and x = 3 for the function f(x) = 3x^3 + 1. Inc

lude the average rate of change in your answer.

Mathematics
1 answer:
Lostsunrise [7]3 years ago
6 0

Answer:

39

Step-by-step explanation:

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A company is paying a local television station to run its commercials. The cost for running commercials is a one-time campaign f
Margarita [4]
The y-intercept is the value of y when x is equal to zero. From the equation,

y = 500 + 50x

the y-intercept is calculated by:

y = 500 + 50(0) = 500

Therefore, the correct answer is option B. The y-intercept is 500; it represents the one-time campaign fee.
8 0
3 years ago
PLEASE HELP ANSWER CORRECTLY !!!!!!!!!!!!!! WILL MARK BRIANLIEST !!!!!!!!!!!!!!
Nina [5.8K]

Hello, hehelol12.

The length of PR is the same as TR.

Length of PR = 11.

The measure of angle PQR is the same as angle RST.

Measure of angle PQR = 39

I hope this helps you out!

PS. Brainliest would be appreciated. :)

4 0
2 years ago
At 2:00 PM a car's speedometer reads 30 mi/h. At 2:10 PM it reads 50 mi/h. Show that at some time between 2:00 and 2:10 the acce
Daniel [21]

Answer: If we define 2:00pm as our 0 in time; then:

at t= 0. the velocity is 30 mi/h.

then at t = 10m (or 1/6 hours) the velocity is 50mi/h

Then, if we think in the "mean acceleration" as the slope between the two velocities, we can find the slope as:

a= (y2 - y1)/(x2 - x1) = (50 mi/h - 30 mi/h)/(1/6h - 0h) = 20*6mi/(h*h) = 120mi/h^{2}

Now, this is the slope of the mean acceleration between t= 0h and t = 1/6h, then we can use the mean value theorem; who says that if F is a differentiable function on the interval (a,b), then exist at least one point c between a and b where F'(c) = (F(b) - F(a))/(b - a)

So if v is differentiable, then there is a time T between 0h and 1/6h where v(T) = 120mi/h^{2}

5 0
3 years ago
Which equation represents the function graphed on the coordinate plane?????
Y_Kistochka [10]

Since you haven't provided the graph, I'll explain each one and you choose the one suiting your given.

<u>The parent modulus function is:</u>

g(x) = |x|

It is centered at the origin and opens upwards.

A coefficient inside the modulus |x+k| means that the function is shifted along the x-axis

If "k" is <u>positive</u>, the shift will be to the <u>left</u>. If "k" is <u>negative</u>, the shift will be to the <u>right</u>.

A coefficient outside the modulus |x| + h means that the function is shifted along the y-axis

If "h" is <u>positive</u>, the shift will be <u>upwards</u>. If "h" is <u>negative,</u> the shift will be <u>downwards</u>.

<u>Now, let's check each of the options:</u>

<u>g(x) = |x+4| - 2 :</u>

This function is shifted 4 units to the left and 2 units down. It will be centered at (-4,-2). Check the blue graph in the attachment.

<u>g(x) = |x-4| - 2 :</u>

This function is shifted 4 units to the right and 2 units down. It will be centered at (4,-2). Check the black graph in the attachment.

<u>g(x) = |x-2| - 4 :</u>

This function is shifted 2 units to the right and 4 units down. It will be centered at (2,-4). Check the red graph in the attachment.

<u>g(x) = |x-2| + 4 :</u>

This function is shifted 2 units to the right and 4 units up. It will be centered at (2,4). Check the green graph in the attachment.

All 4 graphs are shown in the attached picture.

Hope this helps :)


3 0
3 years ago
Read 2 more answers
Ava, Grace, Jayden, and Zoe together stacked a total of 50 brownies on a tray. Ava stacked 0.14 of the brownies, Grace stacked 4
OLEGan [10]

1. Zoe stacked the most brownies. She stacked 27 brownies out of the 50 brownies.

2. 15

3. 43 + 3n ≥ 70, so n ≥ 9

4. D. 58x + 13 + 58y

5. The answer would be ≤4

6. 9.94 + 10.01p ≤ 70, so p ≤ 6

7. C 40 89

8.  D. x+(x+5)=77

Hope I helped you! Please consider marking my answer the brainliest :)

4 0
3 years ago
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