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andrew-mc [135]

3 years ago

13

A point is chosen randomly on JM. Identify the probability that the point is on JK or LM. HELP Please!! I don't understand......

......

1 answer:

Alexus [3.1K]3 years ago

3 0

b. 9/19

should be Correct answer

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Find the slope of the line please help

Alex777 [14]

Answer:

m = -1/3

Step-by-step explanation:

There are two ways that you can use to get this answer.

The first way is to use the graph. You can see that to get from Point A to Point B, the dots go over 1 and down 3. For the fraction, you put the amount that you go to the side (1) over the amount you go down (3) to get 1/3. Since the points go down gradually, the slope is negative, so 1/3 becomes -1/3.

The second way is to take the two points, (1, 4) and (2, 1) and subtract them. First, subtract the x-coordinate from Point B from Point A to get -1. Then do the same thing with the y-coordinates to get 3. Put the -1 over 3 because x comes before y, and you have your slope.

I hope this helped :)

8 0

3 years ago

Is 1/8 greater than 2/10

emmasim [6.3K]

No, 1/8 is smaller because 2/10 is equivalent to 1/5 and 1/5 is larger than 1/8.

3 0

3 years ago

Read 2 more answers

The cylinders are similar. The volume of the larger cylinder is 9648 cubic inches. What is the volume of the smaller cylinder?

zalisa [80]

Hey there :)

The volume formula of a cylinder is:
V = $\pi$ r²h

The volume of the larger volume is given to be 9648³ and the height is 18 in
We need to find the radius first

9648 = $\pi$ r²(18)
$\frac{9648}{18}$ = $\pi$ r²
536 = $\pi$ r²
$\frac{536}{ \pi}$ = r²
$\sqrt{ \frac{536}{ \pi } }$ = r
r ≈ 13.06

The ratio of the big cylinder to small cylinder is:
18 : 9 (given height)
So the big cylinder is 2 times bigger than the small cylinder
Therefore the radius of the big cylinder is as well 2 times bigger

$\frac{13.06}{2} = r$
r ≈ 6.53 ( the radius of the small radius )

V (of small cylinder) = $\pi$ (6.53)²(9)
= 1206 in³

3 0

3 years ago

Blababa [14]

I think the answer is c

4 0

3 years ago

An exponential random variable has a standard deviation of 16. Calculate The probability that it takes on a value < 11. Use 3

antiseptic1488 [7]

Answer:

$P(X$

And using the cdf we got:

$P(X$

Step-by-step explanation:

Previous concepts

The exponential distribution is "the probability distribution of the time between events in a Poisson process (a process in which events occur continuously and independently at a constant average rate). It is a particular case of the gamma distribution". The probability density function is given by:

$P(X=x)=\lambda e^{-\lambda x}, x>0$

And 0 for other case. Let X the random variable that represent the random variable of interest and we know that the distribution is given by:

$X \sim Exp(\lambda)$

We know the variance on this case given by :

$Var(X) = \frac{1}{\lambda^2}$

So then the deviation is given by:

$Sd(X) = \frac{1}{\sqrt{\lambda}}$

And if we solve for $\lambda$ we got:

$\lambda = (\frac{1}{16})^2 = \frac{1}{256}$

The cumulative distribution function for the exponential distribution is given by:

$F(x) = 1- e^{-\lambda x}$

Solution to the problem

And for this case we want to find this probability:

$P(X$

And using the cdf we got:

$P(X$

5 0

3 years ago