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tino4ka555 [31]
4 years ago
11

How to convert fraction to decimal

Mathematics
1 answer:
hammer [34]4 years ago
8 0
To convert a faction to a decimal you have to divide the denominator into the numerator.

1 ÷ 2 = 0.50
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Stella is making 25 sundaes with mint, chocolate, and vanilla ice cream. 1 5 of the sundaes are mint ice cream and 1 2 of the re
o-na [289]

Answer:

Vanilla = 10 sundaes

Step-by-step explanation:

Total sundaes = 25

1/5 of the sundaes are mint ice cream

Mint ice cream = 1/5 of 25

= 1/5 * 25

= 25/5

= 5

Sundaes remaining = total sundaes - sundaes for mint ice cream

= 25 - 5

= 20 sundaes

Sundaes remaining = 20 sundaes

1/2 of the remaining sundaes are chocolate

= 1/2 of 20

= 1/2 * 20

= 20/2

= 10

Chocolate ice cream = 10

The rest will be vanilla

Sundaes remaining = 20 - 10

= 10 sundaes

Vanilla = 10 sundaes

5 0
3 years ago
PLS HELP Anna buys bananas and apples. She buys 2 more apples than twice the number
Alecsey [184]

Answer:

You have to put this in a bar model yourself so convert it later

She bought 10 apples

Step-by-step explanation:

3x + 2 = 14

why i did this

because she bought 2 times the amount of bananas, it should be x + 2x = 3x

then i added two because she bought two extra apples

so 3x+2 = 14

subtract 2

3x = 12

x = 4

So now we substitute x in apples

2x +2 = # of apples

8 +2 = 10

check

10 - 2 = 8

8/2 = 4

4 = # of bananas

4 0
3 years ago
Read 2 more answers
F(x)=x^2-4x-12 on (0,6)
julsineya [31]

the answer is

(x,345)

3 0
3 years ago
Point A is at ( -3, -5) and point M is at (-0.5, 0).
Valentin [98]

Answer:

B(1.25,5)

Step-by-step explanation:

y... -5, 0, 5

x... -0.5, 1.25, 3

6 0
3 years ago
Read 2 more answers
Find the characteristic polynomial and the eigenvalues of the matrix.
Vlada [557]

Answer:

Step-by-step explanation:

Given the matrix

[5 3]

[-4 4]

The characteristic polynomial is expressed as |A - λI| = 0  where λ are the eigen values and I is am identity matrix A 2*2 identity matrix is expressed as;

[1 0]

[0 1]

Substitute into expression will give;

= \left[\begin{array}{cc}5&3\\-4&4\\\end{array}\right]  - \lambda \left[\begin{array}{cc}1&0\\0&1\\\end{array}\right] = 0\\= \left[\begin{array}{cc}5&3\\-4&4\\\end{array}\right]  -  \left[\begin{array}{cc}\lambda &0\\0&\lambda \\\end{array}\right] = 0\\= \left[\begin{array}{cc}5-\lambda&3\\-4&4-\lambda\\\end{array}\right]  = 0

Find the determinant of the resulting matrix;

|A - λI| = (5- λ)(4- λ)- 3(-4) = 0

|A - λI| = 20-5 λ-4 λ+ λ²+12 = 0

|A - λI| = 20-9λ+λ²+12 = 0

-9λ+λ²+32 = 0

Rearrange;

λ²-9λ+32 = 0

Hence the characteristic polynomial is expressed as λ²-9λ+32 = 0

Get the eigen values by finding the roots of the equation;

λ = 9±√9²-4(1)(32)/2

λ = 9±√81-(128)/2

λ = 9±√-47/2

λ = 9±√-47/2

λ₁ = 9-√47 i/2 and λ₂ = 9+√47 i/2

7 0
3 years ago
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