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topjm [15]
3 years ago
12

What is the volume of 11ft*12ft*9ft

Mathematics
1 answer:
masha68 [24]3 years ago
5 0
All you need to do is multiply 
11 x 12 x 9
=1188
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How many 5 digit numbers are even if repetition is not allowed?
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23308 is the answer of how many is even with no repitition
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Giving brainlist easy math problem!
Oliga [24]

Answer:

b = 10

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x = -1.2

Step-by-step explanation:

b = 10 and x = -1.2 only have one variable. You can divide -2 to both sides for -2d = -38 getting d = 19.

0.1 = 0.1 have no variable meaning that any number can be correct in the equation

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3 years ago
If f(x) = 1/9 x - 2, what is f-1 (x)
Snowcat [4.5K]

f(x) =  \frac{1}{9} x - 2 \\

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6 0
3 years ago
Alexander Litvinenko was poisoned with 10 micrograms of the radioactive substance Polonium-210. Since radioactive decay follows
koban [17]

Answer:

The amount of Polonium-210 left in his body after 72 days is 6.937 μg.

Step-by-step explanation:

The decay rate of Polonium-210 is the following:

N(t) = N_{0}e^{-\lambda t}     (1)

Where:

N(t) is the quantity of Po-210 at time t =?

N₀ is the initial quantity of Po-210 = 10 μg

λ is the decay constant  

t is the time = 72 d  

The decay rate is 0.502%, hence the quantity that still remains in Alexander is 99.498%.    

First, we need to find the decay constant:

\lambda = \frac{ln(2)}{t_{1/2}}    (2)

Where t(1/2) is the half-life of Po-210 = 138.376 days

By entering equation (2) into (1) we have:

N(t) = N_{0}e^{-\frac{ln(2)}{t_{1/2}}*t}} = 10* \frac{99.498}{100}*e^{-\frac{ln(2)}{138.376}*72} = 6.937 \mu g    

Therefore, the amount of Polonium-210 left in his body after 72 days is 6.937 μg.  

I hope it helps you!  

8 0
3 years ago
What's 2+2=...........?
mr Goodwill [35]
The answer is 4 (four)
3 0
3 years ago
Read 2 more answers
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