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AveGali [126]
3 years ago
5

En la preparación de un perfume se cuenta con dos tipos de esencia base: 1600 ml de una y 1680 ml de otra. Se quiere envasarlas,

sin mezclar, en el menor número posible de recipientes con la misma capacidad. ¿Cuál es la menor cantidad de frascos que se requieren?
Mathematics
1 answer:
Lostsunrise [7]3 years ago
4 0

Answer:

33,600 frascos

Step-by-step explanation:

Resolvemos esta pregunta utilizando el método mínimo común múltiple

Encuentre y enumere los múltiplos de 1600 y 1680 hasta encontrar el primer múltiplo común. Este es el mínimo común múltiplo.

Múltiplos de 1600:

1600, 3200, 4800, 6400, 8000, 9600, 11200, 12800, 14400, 16000, 17600, 19200, 20800, 22400, 24000, 25600, 27200, 28800, 30400, 32000, 33600, 35200, 36800

Múltiplos de 1680:

1680, 3360, 5040, 6720, 8400, 10080, 11760, 13440, 15120, 16800, 18480, 20160, 21840, 23520, 25200, 26880, 28560, 30240, 31920, 33600, 35280, 36960

Por lo tanto,

LCM (1600, 1680) = 33,600

La menor cantidad de frascos necesarios es 33,600 frascos.

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Answer:

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Step-by-step explanation:

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It is determined that this can't be factored, so rewrite the equation so you can complete the square.

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Take the square of 1.5 and add it to both sides:

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Factor:

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5 0
3 years ago
4 Abi is going to buy ingredients to make 65 hot chocolate drinks.
Semenov [28]

Answer:

To make 65 chocolate drinks, she needs:

12 g of chocolate powder and 5 marshmallows per drink.

Then she needs:

12g*65 = 780 grams of chocolate powder.

We know that the chocolate powder comes in jars of 250g, such that each one costs £2.99

If she buys 3 jars, she will have: 3*250g = 750g

So she will not have enough, then she needs to buy 4 jars.

Then in chocolate powder, she will pay 4 times £2.99 = £11.96

And for marshmallows, she needs:

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Marshmallows come in bags of 120, then the number of packs that Abi needs to buy is:

325/120 = 2.7

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Then she needs 3 bags, and each bag costs £1.45

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8 0
3 years ago
Someone please help on this problem ?
Wewaii [24]

Answer:

CR = 17 ; PR = 30

Step-by-step explanation:

From the problem hypothesis we know that CD⊥PR or CQ⊥PR(perpendicular) and ∡PCQ ≡∡RCQ (bisector)

so ∡PCQ≡∡RCQ

     [CQ]≡[CQ] (common side)

     CQ⊥PR

--------------------------------------------

⇒(cathetus - angle case of congruence)⇒ ΔPQC≡ΔRQC so [PQ]≡[QR] (=15) // PR = PQ+QR ⇒ PR=30

from this congruence ⇒ΔPRC = isosceles so PC=CR=17

Hint: in any triangle is bisector of an angle it is perpendicular on the opposite side then triangle is isosceles.

7 0
3 years ago
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