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Advocard [28]
2 years ago
11

What is the exact distance from (-4, -2) to (3, 8) on the coordinate plane?

Mathematics
1 answer:
Veronika [31]2 years ago
7 0

Answer:

√149 units

Step-by-step explanation:

√(x2 - x1)² + (y2 - y1)²

√[3 - (-4)]² + [8 - (-2)]²

√(7)² + (10)²

√49 + 100

√149

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SUPER EASY
goblinko [34]
<span>3(x + 5) = 3 · x + 3 · 5</span>
6 0
3 years ago
Read 2 more answers
Write the equation of the line in point-slope form.
HACTEHA [7]
Y-4=2/-3(x-6) I believe that’s the answer hope this helped
4 0
3 years ago
Can I take a picture of the problem and upload for you to see?
eduard
Yes you can …………………………
6 0
2 years ago
Consider firing a pumpkin from a canon at a target that is 17 meters away. The pumpkin follows a quadratic path as displayed to
bixtya [17]
A.
(0,00
(2.6,7.9)
(4.8,12.4)
(9.7,15.1)

b.
well, the points don't look like they are on the line but they actually are (plot twist)


so
since (0,0) is on th egarph

0=a(0)²+b(0)+c
0=c
so
f(x)=ax²+bx+0 or
f(x)=ax²+bx

find a and b
sub points

(2.6,7.9)
7.9=a(2.6)²+b(2.6)
7.9=6.76a+2.6b

(4.8,12.4)
12.4=a(4.8)²+b(4.8)
12.4=23.04a+4.8b

use those 2 equations
7.9=6.76a+2.6b
12.4=23.04a+4.8b

eliminate b
multiply first equation by -4.8 and 2nd by 2.6 and add them
-37.92=-32.448a-12.48b
32.24=59.904a-12.48b +
-5.68=27.456a+0b

-5.68=27.456a
divide both sides by 27.456
(-5.68/27.456)=a
find b

12.4=23.04a+4.8b
12.4=(-130.8672/27.456)+4.8b
12.4+(130.8672/27.456)=4.8b
(12.4+(130.8672/27.456))/4.8=b

da equation is
y= \frac{-5.68}{27.456} x^2+ \frac{12.4+\frac{130.8672}{27.456}}{4.8}x



c. the roots are found with your calculator
the roots are at x=0 and x=17.287323943662
so very close to the target but not exactly on it
if the target has a radius of 0.287323943662 or more then it will hit the target
5 0
3 years ago
What is the measure of angle VYZ
irakobra [83]

Answer:

\boxed{\sf C. \ 161 ^{ \circ}}

Step-by-step explanation:

<em>Opposite angles are also congruent angles, meaning they are equal or have the same measurement.</em>

\sf \implies \angle VYZ = \angle WYT \\  \\  \sf \implies(8x  + 1) ^{ \circ}  = (9x  - 19)^{ \circ}  \\  \\  \sf \implies 8x^{ \circ}  + 1^{ \circ}  = 9x^{ \circ}  - 19^{ \circ}  \\  \\  \sf \implies 8x^{ \circ}  - 9x^{ \circ}   + 1^{ \circ} =  - 19^{ \circ}  \\  \\  \sf \implies  - x^{ \circ}   =  - 19^{ \circ}   -   1^{ \circ}  \\  \\  \sf \implies  \cancel{ -} x^{ \circ}   =   \cancel{- }20^{ \circ}    \\  \\  \sf \implies   x^{ \circ}   =  20^{ \circ}

\therefore

\sf \implies \angle VYZ =(8x + 1) ^{ \circ}  \\  \\  \sf \implies \angle VYZ =(8  \times 20 + 1) ^{ \circ}  \\  \\  \sf \implies \angle VYZ =( 160+ 1) ^{ \circ}  \\  \\  \sf \implies \angle VYZ =161 ^{ \circ}

7 0
3 years ago
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