(X-4)-(y+5)=5.4 value of f(3)
Check the picture below. Count them up.
<h3>
Answer: 7/10</h3>
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Explanation:
There are 30 days in April. Since it rained 9 of those days, the empirical probability of it raining in April is 9/30 = (3*3)/(3*10) = 3/10.
If we assume that the same conditions (ie weather patterns) hold for May, then the empirical probability of it raining in May is also 3/10. By "raining in May", I mean specifically raining on a certain day of that month.
The empirical probability of it not raining on the first of May is therefore...
1 - (probability it rains)
1 - (3/10)
(10/10) - (3/10)
(10-3)/10
7/10
We can think of it like if we had a 10 day period, and 3 of those days it rains while the remaining 7 it does not rain.
For starters, v(x) is the same as y If you know how to graph a line in the form of y=mx+b you can graph this. By putting it in the order it becomes: y=2x-5. Slope of 2 and y intercept of -5. that's to graph it
