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schepotkina [342]
2 years ago
8

Your uncle is currently four times as old as you are. In five years, your uncle will be three times as old as you. What is your

current age?
A. 10
B. 8
C. 5
D. 1
Mathematics
1 answer:
sertanlavr [38]2 years ago
8 0

Answer:

your uncle will always be 4 times as old as you if he is currently 4 times as old as you

Step-by-step explanation:

kinda self explanatory so i think its a trick question haha

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A glider plane travels 120 miles in 2 hours. At that rate, how many hours will it take the plane to travel 300 miles?
Nezavi [6.7K]

Answer:

The answer is 4.3

6 0
3 years ago
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The length of a rectangular plot of land is 1Start Fraction 17 over 25 End Fraction times its width. If the width of the plot is
butalik [34]
B 7 yards hope this helps
3 0
3 years ago
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Determine the equation of the graph with the coordinates of (4, -1)
Anon25 [30]

Answer:

The required equation of the graph with the coordinates of (4, -1) will be:

  • y=\left(x-4\right)^2-1

The graph is also attached.

Step-by-step explanation:

Given the coordinates (4, -1)

If we put the coordinate values (4, -1) in the given equations, we determine that only y=\left(x-4\right)^2-1 is the valid equation as it satisfies the given coordinate value.

For example, putting  (4, -1) in the equation

y=\left(x-4\right)^2-1

\left(-1\right)=\left(4-4\right)^2-1

-1=\left(0\right)^2-1

-1=0-1

-1=-1

So, the equation y=\left(x-4\right)^2-1 is true for the coordinate values (4, -1).

Therefore, the required equation of the graph with the coordinates of (4, -1) will be:

  • y=\left(x-4\right)^2-1

Please check, the graph is also attached.

3 0
3 years ago
Consider the following equation: f(x)=x^2+4\4x^2-4x-8 name the vertical asymptote(s)
zhenek [66]

ANSWER

The vertical asymptotes are


\Rightarrow x=2\:or\:x=-1

<u>EXPLANATION</u>

We have

f(x)=\frac{x^2+4}{4x^2-4x-8}


For vertical asymptotes we set the denominator to zero and solve the quadratic equation;

4x^2-4x-8=0


\Rightarrow x^2-x-2=0

We split the middle term to obtain,

x^2+x-2x-2=0

\Rightarrow x(x+1)-2(x+1)=0


\Rightarrow (x-2)(x+1)=0


\Rightarrow x=2\:or\:x=-1


Therefore the vertical asymptotes are


x=2\:or\:x=-1





3 0
3 years ago
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Is 16x^2-36x+25^2 a perfect Square trinomial
yulyashka [42]

Answer:

No, middle term should be 40x.

Step-by-step explanation:

16 {x}^{2}  - 2 \times 4x \times 5 +  {25}^{2}  \\   =  {(4x)}^{2}  - 40x +  {5}^{2}  \\  = (4x - 5)^{2}  \\

Hence, for the given trinomial to be a perfect square its middle term should be 40x and not 36x.

6 0
3 years ago
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