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Dafna11 [192]
2 years ago
6

Classify the following triangle. Check all that apply.

Mathematics
1 answer:
grin007 [14]2 years ago
4 0

Answer:

Isosceles, obtuse triangle

Step-by-step explanation:

The triangle is isosceles since there are equal acute-angles which therefore prove two equal sides.

The triangle is obtuse because it consists of one obtuse angle which is 98 and is greater than 90 degrees.

Hope this helps!!! PLZ MARK BRAINLIEST!!!

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Suppose a geyser has a mean time between eruptions of 72 minutes. Let the interval of time between the eruptions be normally dis
nikitadnepr [17]

Answer:

(a) The probability that a randomly selected time interval between eruptions is longer than 82 ​minutes is 0.3336.

(b) The probability that a random sample of 13-time intervals between eruptions has a mean longer than 82 ​minutes is 0.0582.

(c) The probability that a random sample of 34 time intervals between eruptions has a mean longer than 82 ​minutes is 0.0055.

(d) Due to an increase in the sample size, the probability that the sample mean of the time between eruptions is greater than 82 minutes decreases because the variability in the sample mean decreases as the sample size increases.

(e) The population mean must be more than 72​, since the probability is so low.

Step-by-step explanation:

We are given that a geyser has a mean time between eruptions of 72 minutes.

Also, the interval of time between the eruptions be normally distributed with a standard deviation of 23 minutes.

(a) Let X = <u><em>the interval of time between the eruptions</em></u>

So, X ~ N(\mu=72, \sigma^{2} =23^{2})

The z-score probability distribution for the normal distribution is given by;

                            Z  =  \frac{X-\mu}{\sigma}  ~ N(0,1)

where, \mu = population mean time = 72 minutes

           \sigma = standard deviation = 23 minutes

Now, the probability that a randomly selected time interval between eruptions is longer than 82 ​minutes is given by = P(X > 82 min)

       P(X > 82 min) = P( \frac{X-\mu}{\sigma} > \frac{82-72}{23} ) = P(Z > 0.43) = 1 - P(Z \leq 0.43)

                                                           = 1 - 0.6664 = <u>0.3336</u>

The above probability is calculated by looking at the value of x = 0.43 in the z table which has an area of 0.6664.

(b) Let \bar X = <u><em>sample mean time between the eruptions</em></u>

The z-score probability distribution for the sample mean is given by;

                            Z  =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \mu = population mean time = 72 minutes

           \sigma = standard deviation = 23 minutes

           n = sample of time intervals = 13

Now, the probability that a random sample of 13 time intervals between eruptions has a mean longer than 82 ​minutes is given by = P(\bar X > 82 min)

       P(\bar X > 82 min) = P( \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } > \frac{82-72}{\frac{23}{\sqrt{13} } } ) = P(Z > 1.57) = 1 - P(Z \leq 1.57)

                                                           = 1 - 0.9418 = <u>0.0582</u>

The above probability is calculated by looking at the value of x = 1.57 in the z table which has an area of 0.9418.

(c) Let \bar X = <u><em>sample mean time between the eruptions</em></u>

The z-score probability distribution for the sample mean is given by;

                            Z  =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \mu = population mean time = 72 minutes

           \sigma = standard deviation = 23 minutes

           n = sample of time intervals = 34

Now, the probability that a random sample of 34 time intervals between eruptions has a mean longer than 82 ​minutes is given by = P(\bar X > 82 min)

       P(\bar X > 82 min) = P( \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } > \frac{82-72}{\frac{23}{\sqrt{34} } } ) = P(Z > 2.54) = 1 - P(Z \leq 2.54)

                                                           = 1 - 0.9945 = <u>0.0055</u>

The above probability is calculated by looking at the value of x = 2.54 in the z table which has an area of 0.9945.

(d) Due to an increase in the sample size, the probability that the sample mean of the time between eruptions is greater than 82 minutes decreases because the variability in the sample mean decreases as the sample size increases.

(e) If a random sample of 34-time intervals between eruptions has a mean longer than 82 ​minutes, then we conclude that the population mean must be more than 72​, since the probability is so low.

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3 years ago
PLEASE TELL ME HOW YOU GOT THE ANSWER!!!!!
Lesechka [4]
C is the answer. if the water is being pumped out then the height of the water would decrease.
8 0
3 years ago
Zoe is a salesperson who sells computers at an electronics store. She is paid a 1% commission for every computer sale she makes,
ella [17]

<u>Given:</u>

Zoe gets paid a 1% commission for every sale she makes in addition to base pay.

She sold $8,000 worth of computers on a day and made $140 that day.

<u>To find:</u>

A function P(x) representing total pay on a day where she sells x dollars worth of computers.

<u>Solution:</u>

To determine the function P(x) we need to determine how much Zoe's base pay per day is.

One day, she sold $8,000 worth of computers and made $140 that day.

She gets a commission of 1% for $8,000.

1% of $8,000 = \frac{1}{100} (8,000) = 80.

So she got paid $140 out of which $80 was a commission.

So her base pay = 140-80 = 60.

So Zoe's base pay is $60 a day.

P(x) is the sum of her base pay and 1% of the amount of computer sales she makes ($x).

So P(x) = 60 + (0.01)x, where x is the computer sales she makes in dollars. P(x) is represented in dollars.

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3 years ago
A hat factory makes 2 types of hats. Each day, the factory makes 400 of each type of hat. How many hats does the factory make ea
Lostsunrise [7]
The factory makes a total of 800 hats
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3 years ago
Please help me find the median!
musickatia [10]

The median for this set of data, I believe it is Team Leader. Mostly because the middle wage is Team Leader, along with the wage.

7 0
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