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garik1379 [7]
2 years ago
9

Need help with this

Mathematics
2 answers:
Leya [2.2K]2 years ago
4 0

Answer:

12

Step-by-step explanation:

The least common denominator of the fractions is the least common multiple of the denominators.

Multiples of 3: 3, 6, 9, 12, 15, 18, ...

Multiples of 4: 4, 8, 12, 16, 20, 24, ...

The lowest multiple that is common to 3 and 4 is 12.

LCD of 1/3 and 3/4 is 12.

Lynna [10]2 years ago
3 0

Answer:

1/4

Step-by-step explanation:

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18x = 162

x = 9

There are 9 cartons filled with 18 eggs each, which is 162 eggs in total.
4 0
3 years ago
Share $50 among Tom, Larry and Jim in the ratio 4:7:9. How much money does JIM get?
stiv31 [10]

Answer:

$22.5

Step-by-step explanation:

  • 4x+7x+9x=50
  • 20x=50
  • x=2.5

Jim gets 9*2.5= $22.5

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A math instructor assigns a group project in each of the scenarios below, the instructor selects 5 consecutive students from thi
SVETLANKA909090 [29]

Complete question:

Consider a class of 20 students consisting of 5 sophomores, 8 juniors, and 7 seniors. A math instructor assigns a group project in each of the scenarios below, the instructor selects 5 consecutive students from this class, keeping track (in order) of the level of the student that he gets.

1a. How many possible outcomes are in the sample space S? (An outcome is a 5- tuple of students.)

Let A2 denote the event that exactly 2 of the selected students are sophomore, A5 denote the event that exactly 5 of the selected students are the juniors, and A4 denote the event that exactly 4 of the selected students are seniors.

1b. Find the probabilities of each of these three events. A2, A5, A4

1c. Do the events A2, A5, A4 constitute a partition of the sample space?

Answer:

Given:

n = 20

a) The possible outcome in the sample space,S, =

ⁿCₓ = ²⁰C₅

= \frac{20!}{(20-5)! 5!)}

= \frac{20*19*18*17*16}{5*4*3*2*1}

= 15504

b) probabilities of A2, A5, A4

P(A2) = ⁵C₂ / ²⁰C₂

= \frac{20}{320} = \frac{1}{19}

P(A5) = ⁸C₅ / ²⁰C₅

= \frac{56}{15540} = \frac{7}{1938}

P(A4) = ⁷C₄ / ²⁰C₄

= \frac{35}{4845} = \frac{7}{969}

c) No,the events A2, A5, A4, do not comstitute a partition of the sample space. i.e P(A2)+P(A5)+P(A4) ≠ 1

5 0
3 years ago
Ms. Hamm bought a new car for $37,500. It is said that her car depreciates at a rate of 7% each year
Alona [7]

Answer:

This would mean that the next year her car's value would go down by $2,625. The new value of the car would consequently be $34,875.

<h3><u>Step-by-step explanation:</u></h3>

<em>Here is how you can solve this problem:</em>

  • Okay, so first, let's find 7% of $37,500. To do this, the simple way would be to find first 1% of $37,500.

  • 1% of $37,500 is $375. This is because you are moving the decimal point two spaces to the left.

Now that we know that 1% of $37,500 is $375, let's multiply this value by 7.

  • 375 x 7 = 2625.

  • Subtract 2625 from 37,500.

  • You will get $34,875.

Let's say that the next year, her car value goes down by 7% again.

THIS IS THE IMPORTANT PART:

<em>YOU FIND 7% OF THE NEW VALUE, NOT $37,500. YOU WOULD FIND 7% OF $34,875.</em>

<em>Hope this helps! :) </em>

6 0
2 years ago
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