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3 years ago

16. 15 ft 23 ft 10 ft

Mathematics

1 answer:

amid [387]3 years ago

6 0

Split the trapezoid into a 8.5 by 15 rectangle and a 8 by 8.5 by 10 triangle by dropping a line at the end of the triangular part. It'll be easy to calculate the area from there

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The scale on a map of Virginia shows that 1 centimeter represents 30 miles. The actual distance from Richmond, VA to Washington,

Hoochie [10]

Answer:

3.667

Step-by-step explanation:

30 miles per cm means divide distance by 30 or

110/30 = 3.667

4 0

3 years ago

Find the slope of the line passing through the points given below or state that the slope is undefined. Then indicate whether th

Varvara68 [4.7K]

QUESTION A

The given points are

$(x_1,y_1)=(8,3)$ and $(x_2,y_2)=(9,8)$

The slope can be found using the formula;

$m=\frac{y_2-y_1}{x_2-x_1}$

We substitute the point to obtain;

$m=\frac{8-3}{9-8}$

This simplifies to

$m=\frac{5}{1} =5$

Therefore the slope is 5.

QUESTION 2

A positive slope indicates a rising line

A negative slope indicates a rising line

A zero slope means the line is horizontal.

An undefined slope means the line is vertical.

The correct answer is

A. The line rises from left to right.

3 0

2 years ago

Read 2 more answers

Please help me answer this question. I have the answer but i don’t know how to get to it.

Aleksandr [31]

Answer:

what do you mean

Step-by-step explanation:

what do you mean

7 0

3 years ago

(x - 4/6) = (x + 2/12) what is x please show your work.

Sergio039 [100]

The equation has no solution

4 0

3 years ago

A contractor is required by a county planning department to submit one, two, three, four, or five forms (depending on the nature

Westkost [7]

Answer:

(a) The value of k is $\frac{1}{15}$ .

(b) The probability that at most three forms are required is 0.40.

(d) $P(y)=\frac{y^{2}}{50} ;\ y=1, 2, ...5$ is not the pmf of y.

Step-by-step explanation:

The random variable Y is defined as the number of forms required of the next applicant.

The probability mass function is defined as:

$P(y) = \left \{ {{ky};\ for \ y=1,2,...5 \atop {0};\ otherwise} \right$

(a)

The sum of all probabilities of an event is 1.

Use this law to compute the value of k.

$\sum P(y) = 1\\k+2k+3k+4k+5k=1\\15k=1\\k=\frac{1}{15}$

Thus, the value of k is $\frac{1}{15}$ .

(b)

Compute the value of P (Y ≤ 3) as follows:

$P(Y\leq 3)=P(Y=1)+P(Y=2)+P(Y=3)\\=\frac{1}{15}+\frac{2}{15}+ \frac{3}{15}\\=\frac{1+2+3}{15}\\ =\frac{6}{15} \\=0.40$

Thus, the probability that at most three forms are required is 0.40.

(c)

Compute the value of P (2 ≤ Y ≤ 4) as follows:

$P(2\leq Y\leq 4)=P(Y=2)+P(Y=3)+P(Y=4)\\=\frac{2}{15}+\frac{3}{15}+\frac{4}{15}\\ =\frac{2+3+4}{15}\\ =\frac{9}{15} \\=0.60$

Thus, the probability that between two and four forms (inclusive) are required is 0.60.

(d)

Now, for $P(y)=\frac{y^{2}}{50} ;\ y=1, 2, ...5$ to be the pmf of Y it has to satisfy the conditions:

$P(y)=\frac{y^{2}}{50}>0;\ for\ all\ values\ of\ y \\$
$\sum P(y)=1$

Check condition 1:

$y=1:\ P(y)=\frac{y^{2}}{50}=\frac{1}{50}=0.02>0\\y=2:\ P(y)=\frac{y^{2}}{50}=\frac{4}{50}=0.08>0 \\y=3:\ P(y)=\frac{y^{2}}{50}=\frac{9}{50}=0.18>0\\y=4:\ P(y)=\frac{y^{2}}{50}=\frac{16}{50}=0.32>0 \\y=5:\ P(y)=\frac{y^{2}}{50}=\frac{25}{50}=0.50>0$

Condition 1 is fulfilled.

Check condition 2:

$\sum P(y)=0.02+0.08+0.18+0.32+0.50=1.1>1$

Condition 2 is not satisfied.

Thus, $P(y)=\frac{y^{2}}{50} ;\ y=1, 2, ...5$ is not the pmf of y.

7 0

2 years ago