Need help how to get the answers for 1 and 2 please

Mathematics

1 answer:

Furkat [3]3 years ago

4 0

For question 1, you already have that answered which is correct! for question 2, your answer would be (-2, 3)!

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The perimeter of a rectangle is twice the

Shkiper50 [21]

Answer:

L=16 W=7

Step-by-step explanation:

P=2(L+W)

L=2W+2

46=2(2W+2)+2W

(((7×2)+2)=16×2=32

(16-2)/2=7×2=14

32+14=46 or 16+16+7+7=46

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3 years ago

Which congruence criteria is met in the following scenario?

Arisa [49]

None because the triangles have different lines

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2 years ago

Which number line shows the solution to −6 − (−2)? A number line is shown from negative 10 to 0 to positive 10. There are increm

VARVARA [1.3K]

Answer:

The correct option is A) A number line is shown from negative 10 to 0 to positive 10. There are increments of 2 on either side of the number line. The even numbers are labeled on either side of the number line. An arrow pointing from 0 to negative 6 is shown. Above this, another arrow pointing from negative 6 to negative 4 is shown. A vertical bar is shown at the tip of the arrowhead of the top arrow.

Step-by-step explanation:

Consider the provided expression.

−6 − (−2)

Open the parentheses and change the sign.

−6 − (−2)

−6 + 2

Subtract the numbers.

−4

Now draw this on number line.

First draw a number line is shown from −10 to 0 to 10. with scale of 2 unit on either side of the number line. Draw an arrow pointing from 0 to −6 Which show −6. Above this, another arrow pointing from −6 to −4 which shows −6 − (−2) = −4. A vertical bar is shown at the tip of the arrowhead of the top arrow.

The required number line is shown in the figure 1.

Hence, the correct option is A) A number line is shown from negative 10 to 0 to positive 10. There are increments of 2 on either side of the number line. The even numbers are labeled on either side of the number line. An arrow pointing from 0 to negative 6 is shown. Above this, another arrow pointing from negative 6 to negative 4 is shown. A vertical bar is shown at the tip of the arrowhead of the top arrow.