<span>All organisms reproduce through sexual reproduction as a way of life as the universal genetic code, DNA and genetic inherirances are passed from one generation to another. Reproduction is the mating of the female and male sex cells to produce an offspring with shared attributes from parent cells.</span>
D. An expensive instrument is shared by scientists at a university describes the benefit of membership in a research community
Explanation:
A membership in a research community like university research group is a huge benefit for the researcher.
One of the main advantage is sharing of expensive equipment among the members. The university will be equipped with most of the latest equipment necessary to conduct research like supercomputers, latest imaging equipment, manufacturing units, etc which would otherwise be inaccessible to an individual researcher. The researcher can utilize this huge benefit to conduct various experiments needed for his/her research.
These memberships provides a lot of opportunities to interact with fellow researchers, scientists etc, it provides a platform to showcase each one's research, to discuss various merits and demerits of the research, and to know about other valuable information shared by others.
Answer: The viral nucleic acid is most likely Deoxyribonucleic acid (DNA)
Explanation:
Unlike ribonucleic acid (RNA) where uracil can be found, thymine alongside adenine, cytosine and guanine are only found in DNA.
Thus, the presence of 10% thymine in the newly discovered virus makes its analyzed nucleic acid to be deoxyribonucleic acid (DNA)
Mean for the <u>Geno Code 0</u> is average of those ten values ((-3.97)+(-3.99) +(-5.55)+ (-4.56) + (-4.51) + (-4.2 )+( -4.95) + (-4.56) + (-4 )+ (-5.68))/10= -4.597
Standard deviation formula is √((-3.97- (-4.597)2 )+(-3.99-(-4.597)2) +(-5.55-(-4.597)2)+ (-4.56-(-4.597)2) + (-4.51-(-4.597)2) + (-4.2-(-4.597) 2 )+( -4.95-(-4.597)2) + (-4.56-(-4.597)2) + (-4 -(-4.597)2)+ (-5.68-(-4.597)2))/10= √ (0.39+0.37+0.91+0.001+0.007+0.16+0.12+0.001+0.36+1.17)/10= √0.3489=0.59
Mean for the <u>Geno 1 </u>is -0.25 (calculated on the same way as for Geno 0 with different numbers) and standard deviation for Geno 1 is 0.65.
Mean for <u>Geno 2</u> is 5.241 and standard deviation is 1.038.
2.
If individual Phenotype_Value is 5.11, the corresponding genotype code is Geno code 2 since the value is in the range of values 5.241+- 1.
If individual Phenotype_Value is 5.03 the corresponding genotype code is also Geno code 2.
Since the standard deviation is used to measure the variation (dispersal) of set of data values (how close the values are to the mean value) we can conclude whether are random value is within a certain range.
72 chromatids were present in the present in the primary oocyte during prophase 1 of meiosis.
The primary oocyte contains 72 chromatids during prophase 1 of meiosis as the mature ovum has 18 chromosomes.
The primary oocyte contains 72 chromatids , that means it contains 144 chromosomes. During the first meiotic division, it produces one secondary oocyte and one polar body.
The secondary oocyte has 72 chromatids, which again undergoes second meiotic division and produces mature ovum and second polar body . The mature ovum contains contains 36 chromatids which means it has 18 chromosomes.
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