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Katyanochek1 [597]

3 years ago

13

Which statements describe a parabola? Check all that apply. A parabola is the set of all points equidistant from the directrix a

nd focus. The fixed line is called the vertex of a parabola. The focus is a fixed point inside the parabola. The line of symmetry intersects the focus and directrix. The line of symmetry and the directrix are perpendicular. The parabola intersects the directrix.

2 answers:

katen-ka-za [31]3 years ago

8 0

Answer:

A parabola is the set of all points equidistant from the directrix and focus.

The line of symmetry intersects the focus and directrix

The line of symmetry and the directrix are perpendicular

Step-by-step explanation:

A parabola is the set of all points in a plane that are equidistant from a fixed point (focus) and a line (directrix).

The fixed line of a parabola is known as the directrix of the parabola.

The line of symmetry is a line that passes through the focus and is perpendicular to the directrix. The line of symmetry divides the parabola.

The directrix of a parabola does not intersect touch the parabola

-Dominant- [34]3 years ago

8 0

Answer:

1,3,4,5 are correct

Step-by-step explanation:

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(3 points) Blades of grass Suppose that the heights of blades of grass are Normally distributed and independent, with each heigh

NemiM [27]

The final answer is:

a) P( Y < 42.5 ) = 0.8541

b) P( 39.5 < Y < 40.5 ) = 0.1670.

What is the normal distribution?

A continuous probability distribution for a real-valued random variable in statistics is known as a normal distribution or Gaussian distribution.

If x follows a normal distribution with mean μ and standard deviation σ then the distribution of

$\sum_{i =1}^{n}x_{i}$ follows an approximately normal distribution with a mean $n\mu$ and standard deviation $\sqrt{n }\sigma$

let x be the height of blades of grass

x follows normal distribution with mean = μ = 4 and standard deviation = σ = 0.75.

Y = x1 + x2 +...........+x10

$Y = \sum_{i =1}^{10}x_{i}$

Distribution of Y is normal with,

Mean = $\mu _{y}=10*4 = 40$ and standard deviation $= \sigma _{y}=\sqrt{10}*0.75 = 2.3717$

a)

P( Y < 42.5 )

Using normal distribution formmula,

$f(x)= {\frac{1}{\sigma\sqrt{2\pi}}}e^{- {\frac {1}{2}} (\frac {x-\mu}{\sigma})^2}$

=NORMDIST( x, mean, SD , 1 )

=NORMDIST(42.5, 40, 2.3717, 1 )

=0.8541

P( Y < 42.5 ) = 0.8541

b)

P( 39.5 < Y < 40.5 ) = P( Y < 40.5 ) - P( Y < 39.5 )

Using normal distribution formmula,

$f(x)= {\frac{1}{\sigma\sqrt{2\pi}}}e^{- {\frac {1}{2}} (\frac {x-\mu}{\sigma})^2}$

P( Y < 40.5 ) =NORMDIST(40.5, 40, 2.3717, 1 ) = 0.5835

P( Y < 39.5 ) = NORMDIST(39.5, 40, 2.3717, 1 ) = 0.4165

P( 39.5 < Y < 40.5 ) = 0.5835 - 0.4165 = 0.1670

P( 39.5 < Y < 40.5 ) = 0.1670

Hence, the final answer is:

a) P( Y < 42.5 ) = 0.8541

b) P( 39.5 < Y < 40.5 ) = 0.1670.

To learn more about the normal distribution visit,

brainly.com/question/4079902

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