Below are the choices:
A. 80 mL of the 3.5% solution and 120 mL of the 6% solution
<span>B. 120 mL of the 3.5% solution and 80 mL of the 6% solution </span>
<span>C. 140 mL of the 3.5% solution and 60 mL of the 6% solution </span>
<span>D. 120 mL of the 3.5% solution and 80 mL of the 6% solution
</span>
Let fraction of 3.5% in final solution be p.
<span>p * 3.5 + (1 - p) * 6 = 4.5 </span>
<span>3.5p + 6 - 6p = 4.5 </span>
<span>2.5p = 1.5 </span>
<span>p = 3/5 </span>
<span>3/5 * 200 = 120 </span>
<span>Therefore the answer is B. 120 ml of 3.5% and 80 ml of 6%.</span>
Answer:
I believe it is 9
Step-by-step explanation:
alls I did was add the adults to the students then I divide 375 by 44 I got a weird decimal so I rounded it up to 9
Answer:
The equation of the tangent line passing through the point (-2,3) is
4 x + y +5 =0
Step-by-step explanation:
<u><em>Step(i):-</em></u>
<em>Given that the slope of the tangent</em>
<em> </em>
<em></em>
<em> m = -2( 3-1) = -4</em>
<em>Given point x = -2</em>
<em> y = f(-2) =3</em>
<em>∴The given point ( x₁ , y₁) = ( -2 ,3)</em>
<u><em>Step(ii):-</em></u>
The equation of the tangent line passing through the point (-2,3)
![y - y_{1} = m(x-x_{1} )](https://tex.z-dn.net/?f=y%20-%20y_%7B1%7D%20%3D%20m%28x-x_%7B1%7D%20%29)
![y -3 = -4(x-(-2))](https://tex.z-dn.net/?f=y%20-3%20%3D%20-4%28x-%28-2%29%29)
y -3 = -4( x+2)
y-3 = -4x -8
4x + y -3+8=0
4x +y +5=0
<u><em>Step(iii):-</em></u>
<em>The equation of the tangent line passing through the point (-2,3) is</em>
<em> 4 x + y +5 =0</em>
<em></em>