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n200080 [17]
4 years ago
10

2. Order the numbers from least to greatest.

Mathematics
2 answers:
kari74 [83]4 years ago
8 0

Answer:

-5, -2, -1, 0, 7

the answer is D

Step-by-step explanation:

max2010maxim [7]4 years ago
8 0
The answer is D. -5, -2, -1 0, 7
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When Lisa started at her current job, her employer gave her 2 days of paid
Novay_Z [31]

a. The equation computed shows that the number of paid vacation days has she earned will be 17 days.

b. The time when she will reach the maximum number of paid vacation days allowed is 6 years.

<h3>How to compute the equation?</h3>

a. The equation computed shows that the number of paid vacation days has she earned will be:

= 2 + 3x

x = 5

= 2 + 3(5)

= 2 + 15

= 17 days.

b. The maximum number of days for a pod vacation will be:

= 4 × 5

= 20 days.

The time when she will reach the maximum number of paid vacation days allowed will be:

20 = 3x + 2

3x = 20 - 2.

3x = 18

x = 18/3

x = 6 years

Learn more about equations on:

brainly.com/question/28311379

#SPJ1

7 0
2 years ago
<img src="https://tex.z-dn.net/?f=%20%7Ba%7D%5E%7B4%20%20%7D%20%20%20%5Ctimes%20%20%7Ba%7D%5E%7B5%7D%20" id="TexFormula1" title=
tekilochka [14]
The answer would be a^9 (a to the ninth power) because you would add the exponents.
5 0
3 years ago
A web-based company has a goal of processing 95 percent of its orders on the same day they are received. If 485 out of the next
HACTEHA [7]

Answer:

The null hypothesis was rejected.

Conclusion: The proportions of orders completed on the day of receiving is more than 95%.

Step-by-step explanation:

The hypothesis can be defined as:

<em>H₀</em>: The proportions of orders completed on the day of receiving is not more than 95%, i.e. <em>p</em> ≤ 0.95.

<em>Hₐ</em>: The proportions of orders completed on the day of receiving is more than 95%, i.e. <em>p</em> > 0.95.

The significance level of the test is <em>α</em> = 0.025.

The sample size is, <em>n</em> = 500.

As the sample size is large, the sampling distribution of sample proportion can be approximated by the Normal distribution.

The mean and standard deviation of this distribution are:

\mu=p\\\sigma=\sqrt{\frac{p(1-p)}{n}}

The test statistic is:

z=\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n}} }

The sample proportion is:

\hat p=\frac{X}{n}=\frac{485}{500}=0.97

Compute the test statistic as follows:

z=\frac{0.97-0.95}{\sqrt{\frac{0.95(1-0.95)}{500}} }=2.05

The decision rule is:

If the <em>p</em>-value is less than the significance level <em>α</em> then the null hypothesis is rejected.

Compute the <em>p</em>-value as follows:

p-value=P(Z>2.05)\\=1-P(Z

*Use a <em>z</em>-table.

The <em>p</em>-value = 0.0202 < <em>α</em> = 0.025.

The null hypothesis will be rejected.

<u>Conclusion</u>:

As the null hypothesis was rejected at 2.5% level of significance, it can be concluded that the proportions of orders completed on the day of receiving is more than 95%.

3 0
3 years ago
Read 2 more answers
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