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sasho [114]
3 years ago
14

What’s the answers to math problems I have lots of troubles in math but the teach won’t help me ?

Mathematics
1 answer:
leva [86]3 years ago
3 0

If your teacher isn’t teaching you I suggest you talk to a higher ranked staff member instead.

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I have 18 ones 15 hundreds 15 tens 8thousands what number am I
tankabanditka [31]
8 thousands is equal to 8000.
15 hundreds is equal to 1500.
15 tens is equal to 150.
18 ones is equal to 18.

So just add them up.
8000 + 1500 = 9500.
9500 + 150 = 9650.
9650 + 18 = 9668.

The number is 9668
5 0
3 years ago
There are two numbers, one is 7 more than twice the other. The sum of the numbers is 43. Make the equation to find the smaller n
Mrrafil [7]

Answer:

Smaller number: 12

Greater number: 31

Step-by-step explanation:

Hi there!

Let x equal to the smaller number.

Let y be equal to the greater number.

<u>1) Translate the information into equations</u>

"One is 7 more than twice the other"

⇒ y=2x+7

"The sum of the numbers is 43"

⇒ x+y=43

<u>2) Use substitution to solve for the smaller number</u>

x+y=43

Plug the equation y=2x+7 into the above equation

x+(2x+7)=43\\x+2x+7=43\\3x+7=43

Subtract both sides by 7

3x+7-7=43-7\\3x=36

Divide both sides by 3 to isolate x

\frac{3x}{3} = \frac{36}{3} \\x=12

Therefore, the smaller number equates to 12.

<u>3) Use substitution to solve for the greater number</u>

x+y=43

Plug in x as 12

12+y=43

Subtract both sides by 12 to isolate y

12+y-12=43-12\\y=31

Therefore, the greater number equates to 31.

I hope this helps!

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3 years ago
Where t is the number of years since 1997 and y is the number of camera phones shipped(in millions). How many camera phones were
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Not enough information if that is an option
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D is the one that has no solution
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In order to circumscribe a circle on a triangle, which line must you construct?
GalinKa [24]
We need to construct the perpendicular bisectors of at least two of the three sides.

The perpendicular bisector is the locus of points that ensures equal distance between any point on the line and the two ends of the segment. 

The intersection of the two or three (congruent) perpendicular bisectors is the centre of the circumcircle.
5 0
3 years ago
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