9.1/3575
use long division like this
_<u>0.</u>_________
3575|91.000000
we find how many of 3575 fit into the 91
it's too big so we go farther
how many 3575 go into 910
too big so we go farther
how many 3575 go into 9100
the answer is 2 so put that in the correct place and mulitply that and put that in the correct place. then we subtract
_<u>0.</u><u>02</u>_________
3575|91.000000
-<u>71.50</u>
19.50
bring down the next number
find how many go into 19.500
the answe ris 5
_<u>0.</u><u>02</u><u>5</u>_________
3575|91.000000
-<u>71.50</u>
19.500
-<u>17.875</u>
1.625
bring down he next zero ( I fast forward and skip steps for convinience)
__
_<u>0.</u><u>02</u><u>5</u><u>455</u>_________
3575|91.000000
-<u>71.50</u>
19.500
-<u>17.875</u>
1.6250
-<u>1.4300</u>
.19500
-<u>.17875
</u> 16250
-14300
and so on untill infinity so the answe ris 0.0254555555555555 (enless fives)
It would be (rounded) 5
Because
31 / 6.15 = 5.04065
Hope this helped
Have a great day/night
Some things you need to know:
1) You need to know how to convert standard form to slope y-int. form and slope y-int. form to standard form.
2) When two lines are parallel, the slopes are the same.
3) When two lines are perpendicular, the slopes are negative reciprocals of each other. (Or their product is -1)
example: 3/4 --> -4/3.
3/4 * -4/3 = -12/12 = -1
4) To find the value of b, substitute the point into the equation.
5) Convert the equation to slope y-int. form to find the slope.
6) When a line has an undefined slope, the slope y-int. will look either like
y = __ (forms horizontal line) or x = __ (forms vertical line).
To find the perpendicular of these lines, turn y to x / x to y.
To find the value of __, look at the point located in the line, so if x = ___
passes through (5,3), then x = 5 because x = 5 in the point. So the
equation would be x = 5.
Use online practice tests and other sources if you don't understand.
<em>θ</em> is given to be in the fourth quadrant (270° < <em>θ</em> < 360°) for which sin(<em>θ</em>) < 0 and cos(<em>θ</em>) > 0. This means
cos²(<em>θ</em>) + sin²(<em>θ</em>) = 1 ==> sin(<em>θ</em>) = -√[1 - cos²(<em>θ</em>)] = -3/5
Now recall the double angle identity for sine:
sin(2<em>θ</em>) = 2 sin(<em>θ</em>) cos(<em>θ</em>)
==> sin(2<em>θ</em>) = 2 (-3/5) (4/5) = -24/25