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Oduvanchick [21]
3 years ago
14

If ,f(x)=3x-6/x-2 what is the average rate of change of f(x) over the interval [6, 8]?

Mathematics
2 answers:
sukhopar [10]3 years ago
4 0
I hope this helps you



f (x)= 3 (x-2)/(x-2)


f (x)= 3


f(6)= 3


f (8)= 3
enyata [817]3 years ago
3 0

Answer:

the average rate of change of f(x) over the interval [6, 8] is, 0

Step-by-step explanation:

Average rate of change (A(x)) of f(x) over interval [a, b] is given by:

A(x) = \frac{f(b)-f(a)}{b-a}       ....[1]

As per the statement:

Given the function:

f(x) = \frac{3x-6}{x-2}

At x = 6

f(6) = \frac{3(6)-6}{6-2}=\frac{18-6}{4}=\frac{12}{4} =3

⇒f(6) = 3

At x = 8

f(8) = \frac{3(8)-6}{8-2}=\frac{24-6}{6}=\frac{18}{6} =3

⇒f(8) = 3

We have to find the average rate of change of f(x) over the interval [6, 8]

Substitute the given values in [1] we have;

A(x) = \frac{f(8)-f(6)}{8-6}=\frac{3-3}{2}=\frac{0}{2} = 0

Therefore, the average rate of change of f(x) over the interval [6, 8] is, 0

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What is 27+3÷ 3 +4-1+72.4-34.24+6-4+75÷5 <br> Answer this fast please!
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Answer:

86.16

Step-by-step explanation:

27+3÷ 3 +4-1+72.4-34.24+6-4+75÷5

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Multiply and divide first

3/3 is 1   and 75/5 = 15

Replace these into the equation

27+1 +4-1+72.4-34.24+6-4+15

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A random sample of 102 full-grown lobsters had a mean weight of 16 ounces and a standard deviation of 3.4 ounces. Construct a 98
pshichka [43]

Answer:

The best point estimate for a confidence interval estimating the population μ is 16 ounces.

The 98 percent confidence interval for the population mean μ is between 15.21 ounces and 16.79 ounces.

Step-by-step explanation:

We have the standard deviation for the sample, so we use the t-distribution to solve this question.

The best point estimate for a confidence interval estimating the population μ is

The sample mean, so 16 ounces.

T interval

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 102 - 1 = 101

98% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 101 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.98}{2} = 0.99. So we have T = 2.36

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 2.36\frac{3.4}{\sqrt{102}} = 0.79

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 16 - 0.79 = 15.21 ounces

The upper end of the interval is the sample mean added to M. So it is 16 + 0.79 = 16.79 ounces

The 98 percent confidence interval for the population mean μ is between 15.21 ounces and 16.79 ounces.

4 0
2 years ago
1. Evaluate the function f(x)=3x-1 using the domain of -2, 0, 3, and 5. Results are to be shown in a table.
IceJOKER [234]

Answer:

See explanation

Step-by-step explanation:

You are given the function f(x)=3x-1

The domain of the function are all possible values of variable x, so you can find f(x) for x=-2, 0, 3, 5:

f(-2)=3\cdot (-2)-1=-6-1=-7\\ \\f(0)=3\cdot 0-1=0-1=-1\\ \\f(3)=3\cdot 3-1=9-1=8\\ \\f(5)=3\cdot 5-1=15-1=14

The table is

\begin{array}{cc}x&f(x)\\-2&-7\\0&-1\\3&8\\5&14\end{array}

The inverse function f^{-1}(x) has the domain which is the range of the function f(x) (all possible values of f(x)), so the domain of inverse function is {-7,-1,8,14}

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3 years ago
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