<span>( 5, 2) and ( 6, 4)
slope m = (4-2)/(6-5) = 2
y = mx + b
b = y - mx
b = 2 - 2(5)
b = 2 - 10
b = -8
so now you have slope m = 2 and y intercept b = -8
equation
y = 2x - 8
answer
</span><span>a. y = 2x - 8</span>
Answer:

The polynomial is an approximation with an error less than or equals to <em>0.002652</em> for x in the interval
[-1.113826815, 1.113826815]
Step-by-step explanation:
According to Taylor's theorem
with
for some c in the interval (-x, x)
In the particular case f
<em>f(x)=cos(x)
</em>
<em>
</em>
we have
therefore
and the polynomial approximation of T5(x) of cos(x) would be
In order to find all the values of x for which this approximation is within 0.002652 of the right answer, we notice that
for some c in (-x,x). So
and we must find the values of x for which
Working this inequality out, we find
Therefore the polynomial is an approximation with an error less than or equals to 0.002652 for x in the interval
[-1.113826815, 1.113826815]
Horizontal means zero slope, or a zero coefficient on x.
Answer: y = b
Answer:
x + y = 13
98x + 115y = z
Step-by-step explanation:
Let x represent the time spent taking class in Westside community college
Let y represent the time spent taking class in Pinewood community college
Let z represent the combined total amount paid for the class fees.
The total combined time for the two school is given as:
x + y = 13.
For the combined total amount; we multiply the price for each school with the time spent on the school and sum them together.
Westside: 
Pinewood: 
The combined total amount represented as z is given as:
z = 98x + 115y
Answer:
Part A : y²(x + 2)(x + 4)
Part B: (x + 4) (x + 4)
Part C: (x + 4) (x - 4)
Step-by-step explanation:
Part A: Factor x²y²+ 6xy²+ 8y²
x²y²+ 6xy²+ 8y²
y² is very common across the quadratic equation , hence
= y² (x² + 6x + 8)
= (y²) (x² + 6x + 8)
= (y²) (x² + 2x +4x + 8)
= (y²) (x² + 2x)+(4x + 8)
= (y²) (x(x + 2)+ 4(x + 2))
= y²(x+2)(x+4)
Part B: Factor x² + 8x + 16
x² + 8x + 16
= x² + 4x + 4x + 16
= (x² + 4x) + (4x + 16)
= x( x + 4) + 4(x + 4)
= (x + 4) (x + 4)
Part C: Factor x² − 16
= x² − 16
= x² + 0x − 16
= x² + 4x - 4x - 16
= (x² + 4x) - (4x - 16)
= x (x + 4) - 4(x + 4)
= (x + 4) (x - 4)