This makes no sense srry, rephrase it correctly pls in order for me to answer it :P
The probability that the sample proportion is within ± 0.02 of the population proportion is 0.3328
<h3>How to determine the probability?</h3>
The given parameters are:
- Sample size, n = 100
- Population proportion, p = 82%
Start by calculating the mean:



Calculate the standard deviation:



Within ± 0.02 of the population proportion are:


Calculate the z-scores at these points using:

So, we have:


The probability is then represented as:
P(x ± 0.02) = P(-0.43 < z < 0.43)
Using the z table of probabilities, we have:
P(x ± 0.02) = 0.3328
Hence, the probability that the sample proportion is within ± 0.02 of the population proportion is 0.3328
Read more about probability at:
brainly.com/question/25870256
#SPJ1
The answer is 9:16 just add 9+7=16 and then we know out of the 16 nine were dogs so 9:16
2X+8=x-6
2x-x=-6-8
X=-6-8
X=-14
Answer:
, here we go there your answer hope it will helpful