Answer:
The equation for the distance Jane's trainer bikes is
.
Step-by-step explanation:
We have attached diagram for your reference.
Given:
Distance traveled on bike towards south = 16 miles
Distance she ran towards west = 12 miles
We need to find distance Jane's trainer bikes.
Solution:
Let the distance Jane's trainer bike be 'x'.
Now we will assume it to be right angled triangle.
So by Pythagoras theorem which states that;
"Square of the third side is equal to the sum of square of the other two sides."
framing in equation form we get;

Hence the equation for the distance Jane's trainer bikes is
.
On solving we get;

Hence Jane's trainer bikes a distance of 20 miles.
Answer:
200
Step-by-step explanation:
12% is equal to 12/100
I would set up something like
12/100= 24/x
to get from 12 to 24, you have to multiply by 2.
do the same for 100 so 100 x 2= 200
Answer:
7sqrt(15) - 5sqrt(6)
------------------------------
45
Step-by-step explanation:
7 -sqrt(10)
-----------------------
3 sqrt(5) *sqrt(3)
7 -sqrt(10)
-----------------------
3 sqrt(15)
Multiply the top and bottom by sqrt(15)/ sqrt(15)
7 -sqrt(10) sqrt(15)
----------------------- * ------------
3 sqrt(15) sqrt(15)
(7 -sqrt(10))* sqrt(15)
-----------------------------------
3 *15
Distribute
7sqrt(15) - sqrt(150)
------------------------------
45
sqrt(ab) =sqrt(a) sqrt(b)
150 = 25*6
7sqrt(15) - sqrt(25)sqrt(6)
------------------------------
45
7sqrt(15) - 5sqrt(6)
------------------------------
45
Answer:
for Lena
C = 3x C + 5x
for Patrick
C = 9x C = 10x
for total C = 12x + 15x
Step-by-step explanation: